By either long or synthetic division, it's easy to show that

The quartic will be exactly divisible by

when the numerator of the remainder term vanishes, or for those values of

such that

I'm not sure how to count the number of solutions (software tells me it should be 80), but hopefully this is a helpful push in the right direction.
<u>Answer:</u>
The correct answer options are C.
and D.
.
<u>Step-by-step explanation:</u>
The values which make the denominator equal to zero are called the excluded values.
Here, we can substitute 8 for x and check if it makes the denominator 0.





Answer/Step-by-step explanation:
-33 is not a whole number. A whole number is a number(positive) that contains no decimals nor fractions.
Domain values represent possible x values that are allowed to be plugged in and produce a y value. The values (in this case value) that are not allowed to be plugged in are what make the denominator zero (since you cannot divide by zero). Simply set the denominator equal to zero to figure out this value.
3x + 8 = 0
3x = -8
x= -8/3, this value is not in the domain.
The possible values of x are 3 and 7
<h3>Solving rational expressions</h3>
Given the rational expression below;
√60-8x = x - 9
Square both sides to have:
(60-8x)² = (x-9)²
60-8x = x²-18x+81
Equate to zero to have;
x²-18x+81 - 60 + 8x = 0
x² - 10x + 21 = 0
x² -3x-7x +21 = 0
x(x-3)-7(x-3) = 0
x = 3 and 7
Hence the possible values of x are 3 and 7
Learn more on rational expression here: brainly.com/question/25292194
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