Suppose:
C=cost
c=cost per kilo-watt hour
w=number of watts
h=number of hours
thus
C=kwhc
where:
k=constant of proportionality:
k=C/(whc)
but
C=15 when w=6000, h=10/60=1/6 hours, c=7.5 cents per kw/h
thus
k=15/(6000*1/6*7.5)
k=0.002
thus:
C=0.002(whc)
hence:
when
h=70*2=140=140/6=70/3 hours the cost will be:
C=0.002(6000*70/3*7.5)
C=2100 cents
C=$21
F(t)= $100 x h + 300 A reasonable domain is (1,2,3) and the range is ($400,$500,$600)
Answer:
Standard error (S.E) = 0.048 ≅ 0.05
Step-by-step explanation:
<u>Explanation</u>:-
Given sample size 'n'=76
Given the dean who randomly selects 76 students and finds that 58 out of 76 are receiving financial aid.
Sample proportion

The standard error is determined by

Standard error is 0.048 ≅ 0.05
Answer:
there are 10 black pensoles
Step-by-step explanation:
Answer:
a
Step-by-step explanation:
go it right on a mastery test