Check the picture below.
well, the length of the tunnel is "h", now two 8 meters cars, that's 8+8=16 meters plus a 3 meter connector between them, that's 16 + 3 = 19 meters, can those two cars connected like so fit inside the tunnel? sure thing, "h" can fit 19 meters just fine.
Solution
The table below is the required sample space of the to fair die
From the above table
The sample space contain 36 outcomes
Event A: The sum is greater than 9
we will look at the table and count all the elements that are greater than 9
There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)
The probability for event A will be
P(A) = 1/6
Event B: The sum is an even number.
We will look at the table and count the number of elements that are even
There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)
The probability for event B will be
p(B) = 1/2
