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Rasek [7]
3 years ago
14

a scientist has 350 mg of radioactive material. the material is cut in half every 2 hours. how much will be left after 10 hours?

Mathematics
2 answers:
marin [14]3 years ago
4 0
If you cut it in half every two hours, the answer will be 10.9375 mg. 
Rudiy273 years ago
4 0
Idk I just need points ;D
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Which characteristics describe the scatterplot? Check all that apply.
denpristay [2]

Answer:

1. Negative Correlation

3. Strong Correlation

5. Linear

Step-by-step explanation:

We have been given a scatter-plot. We are asked to choose the characteristics of the given scatter-plot.

Upon looking at our given scatter-plot, we can see that as the values of x are increasing values of y are decreasing.

We know that the relationship between two variables in which one variable increases as the other decreases is known as negative correlation. Therefore, the given scatter-plot represents negative correlation and 1st option is a correct choice.

We can also see that the slope of the line connecting all data points is approximately -1, which represents a strong negative correlation, therefore, 3rd option is correct as well.

If we draw a line on our given scatter-plot, it will connect all the data points. Therefore, the given scatter-plot has a linear correlation and 5th option is correct as well.

6 0
3 years ago
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What is the slope of the line represented by the equation y = 4/5x-3
icang [17]

Answer:

<em>m</em> = 4/5

General Formulas and Concepts:

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define Equation</u>

y = 4/5x - 3

<u>Step 2: Break Function</u>

<em>Identify Parts</em>

Slope <em>m</em> = 4/5

y-intercept <em>b</em> = -3

7 0
3 years ago
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A chemical company makes two brands of antifreeze. The first brand is 20% pure antifreeze, and the second brand is 70% pure anti
andre [41]

Answer:

First brand of antifreeze: 21 gallons

Second brand of antifreeze: 9 gallons

Step-by-step explanation:

Let's call A the amount of  first brand of antifreeze. 20% pure antifreeze

Let's call B the amount of second brand of antifreeze. 70% pure antifreeze

The resulting mixture should have 35% pure antifreeze, and 30 gallons.

Then we know that the total amount of mixture will be:

A + B = 30

Then the total amount of pure antifreeze in the mixture will be:

0.2A + 0.7B = 0.35 * 30

0.2A + 0.7B = 10.5

Then we have two equations and two unknowns so we solve the system of equations. Multiply the first equation by -0.7 and add it to the second equation:

-0.7A -0.7B = -0.7*30

-0.7A -0.7B = -21

-0.7A -0.7B = -21

               +

0.2A + 0.7B = 10.5

--------------------------------------

-0.5A = -10.5

A = \frac{-10.5}{-0.5}

A = 21\ gallons

We substitute the value of A into one of the two equations and solve for B.

21 + B = 30

B = 9\ gallons

3 0
3 years ago
A cone and a cylinder have the same height and their bases are congruent circles
Anettt [7]

Answer:

30cm^3

Step-by-step explanation:

the volume of a cylinder is given by:

v_{cylinder}=\pi r^2 h

and the volume of a cone is given by:

v_{cone}=\frac{\pi r^2 h}{3}

since both have the same height and radius, we can solve each equation for r^2h (because this quantity is the same in both figures) and then match the expressions we find:

from the cylinder's volume formula:

r^2h=\frac{v_{cylinder}}{\pi}

and from the cone's volume formula:

r^2h=\frac{3 v_{cone}}{\pi}

matching the two previous expressions:

\frac{v_{cylinder}}{\pi} =\frac{3v_{cone}}{\pi}

we solve for the volume of a cone v_{cone}:

v_{cone}=\frac{\pi v_{cylinder}}{3\pi} \\\\v_{cone}=\frac{v_{cylinder}}{3}

substituting the value of the cylinder's volume v_{cylinder}=90cm^3

v_{cone}=\frac{90cm^3}{3} \\\\v_{cone}=30cm^3

5 0
3 years ago
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Pleas help me find the composition of goh and it’s domain
Ksivusya [100]

Solution:

The function is given below as

\begin{gathered} g(x)=\frac{x+4}{x-1} \\ h(x)=2x-1 \end{gathered}

To figure out

(goh)(x)

To do this , we will substitute x= 2x-1 in g(x)

\begin{gathered} g(x)=\frac{x+4}{x-1} \\ g(h)(x)=\frac{2x-1+4}{2x-1-1} \\ g(h)(x)=\frac{2x+3}{2x-2} \end{gathered}

Hence,

The composte function will be

(goh)(x)=\frac{2x+3}{2x-2}

Step 2:

To figure out the domain,

In mathematics, the domain of a function is the set of inputs accepted by the function.

Hence,

The domain of the function is

\begin{bmatrix}\mathrm{Solution:}\:&\:x1\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:1\right)\cup \left(1,\:\infty \:\right)\end{bmatrix}

5 0
1 year ago
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