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olasank [31]
3 years ago
5

The perimeter of parallelogram ABCD is 46 inches.What is DA?

Mathematics
1 answer:
Shkiper50 [21]3 years ago
4 0

Answer:

3

Step-by-step explanation:

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Wx+yz=bc , solve for z .
Aleksandr-060686 [28]
Wx+yz=bc
minus wx on both sides
yz=bc-wx
dividing 'y' on both sides
Hence,
z=(bc-wx)/y
Here is what you need.
Hope it helped
8 0
3 years ago
Read 2 more answers
In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE ║ AB . If m∠ADE is with 34° smaller than m∠CAB, find the measures
klemol [59]

Answer:

68, 78,34  dreegs

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
What is the slope-intercept form in the picture
grandymaker [24]

Answer:

y= 3/2x+40

Step-by-step explanation:

y= rise/run+ y-intercept

5 0
3 years ago
This Question: 1 pt
zhenek [66]

\huge{ \mathfrak{  \underline{ Answer }\:  \:  ✓ }}

Angles forming linear pair are :

\mathrm{\angle EFG  \:  \: and \:  \:   \angle GFH}

And we know, they are supplymentary

  • \mathrm{\angle EFG  \:   +  \:   \angle GFH}  = 180 \degree
  • 3n +1 9 \degree+ 2n + 36\degree = 180 \degree
  • 5n + 55\degree = 180\degree
  • 5n = 125\degree
  • n = 25\degree

So, the measures of the given angles are :

  • \mathrm{\angle EFG } = 3n + 19
  • \mathrm{ \angle EFG = (3  \times 25\degree)  + 19}
  • \mathrm{ \angle EFG = 75 \degree+ 19\degree}
  • \mathrm{ \angle EFG = 94\degree}

And

  • \mathrm{ \angle GFH = 2n + 36}
  • \mathrm{ \angle  GFH = (2 \times 25\degree) + 36\degree}
  • \mathrm{ \angle GFH = 50\degree + 36\degree}
  • \mathrm{ \angle GFH = 86\degree }

_____________________________

\mathrm{ ☠ \: TeeNForeveR \:☠ }

6 0
3 years ago
A police department in a small city consists of 10 officers. If the department policy is to have 5 of the officers patrolling th
meriva

Answer:

2,520

Step-by-step explanation:

The number of possible arrangements of officers patrolling the streets is the combination of choosing 5 officers out of 10 (₁₀C₅). After choosing the patrolling officers, the number of arrangements for the officers working full time at the station is given by the combination of choosing 2 officers out of the 5 remaining (₅C₂). The remaining officers should be on reserve at the station (₃C₃). The total number of arrangements is:

N = _{10}C_5*_5C_2*_3C_3\\N=\frac{10!}{(10-5)!5!} *\frac{5!}{(5-2)!2!}*\frac{3!}{(3-3)!3!} \\N=2,520

There are 2,520 possible divisions.

5 0
3 years ago
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