All categories

3 years ago

The perimeter of parallelogram ABCD is 46 inches.What is DA?

Mathematics

1 answer:

Shkiper50 [21]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

If NO=17 and NP=5x-6, what is the value of X. Also how do you find X.

Anarel [89]

Are NO and NP congruent?

7 0

2 years ago

Ok pls help this needs to be answered fast

horrorfan [7]

Answer:

the oeange will be there for u

Step-by-step explanation:

1 then 4 then 3 then 6 then 2

8 0

3 years ago

Use the interactive to graph a line with a slope of zero and passing through the 0,4

Gwar [14]

Answer:

You need to draw a horizontal line that goes through the point (0,4).

Step-by-step explanation:

Slope of zero means it does not go up or down. It looks like this ↔, but stretched out to the two sides of the graph.

5 0

3 years ago

8x7+4-10SOMEONE HELP PLS AND THANK U:)

pychu [463]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago