Answer:
P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Step-by-step explanation:
Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3
Basis: P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:
2(k+1) - 1 = 2k + 2 - 1
≤ 2 + k! (by the inductive hypothesis)
= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.
Both 28 I think I just multiplied 7×4 and on the light side is still the same length so that means that is also 4 for A
Answer:
D) a8 = 35 - (n - 1)(3)
Step-by-step explanation:
Answer:
648
Step-by-step explanation:
Write 162% as 162
/100
Since, finding the fraction of a number is same as multiplying the fraction with the number, we have
162
/100 of 400 = 162
/100
× 400
Therefore, the answer is 648
If you are using a calculator, simply enter 162÷100×400 which will give you 648 as the answer
Answer:
3/4 more of flour
Step-by-step explanation:
1/2=2/4
2/4+3/4=1 1/4
