AB(aq)+C >A +CB(aq)
hope this helps
Answer:
32.25 J
Explanation:
Heat, H = ?
Mass, m = 5g = 5 / 1000 = 0.005 Kg
Initial Temperature = 75.0° C
Final Temperature = 25.0° C
Temperature change, ΔT = Final - Initial = 50° C
Specific heat capacity of lead, C = 129 (J/kg°C)
The relationship between these quantities is given by the equation
H = mCΔT
H = 0.005 * 129 * 50
H = 32.25 J
A solution contains 12 g of glucose in 240 mL of solution. What is the mass/volume % of the solution? 5.0% (m/v). Calculate the grams of KCl in 225 g of an 8.00 % (m/m) KCl solution
Answer:
The true statements are given below.
Explanation:
1 D glucose is a reducing sugar
2 The oxidation of reducing sugar forms a carboxylic acid sugar.
D glucose is a reducing sugar because glucose contain a free hydroxyl group (-OH)in its anomeric carbon.
The oxidation of reducing sugar result in the conversion of -CHO group in case of aldose sugar and -CH2OH group in case of ketose sugar into carboxylic acid(-COOH).
5.60 cuz I I’m dumb vendbsnksnddn
