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Rudik [331]
3 years ago
14

Manganese commonly occurs in nature as a mineral. The extraction of manganese from the carbonite mineral rhodochrosite, involves

a two-step process. In the first step, manganese (II) carbonate and oxygen react to form manganese (IV) oxide and carbon dioxide: 2 MnCO3(s) + O2(g) → 2MnO2(s) + 2CO2(g) In the second step, manganese (IV) oxide and aluminum react to form manganese and aluminum oxide: 3 MnO2(s) + 4 Al(s) → 3 Mn(s) + 2 Al2O3(s) Write the net chemical equation for the production of manganese (II) carbonate, oxygen and aluminum. Be sure your equation is balanced.
Chemistry
1 answer:
hjlf3 years ago
5 0

This is an incomplete question, here is a complete question.

Manganese commonly occurs in nature as a mineral. The extraction of manganese from the carbonite mineral rhodochrosite, involves a two-step process. In the first step, manganese (II) carbonate and oxygen react to form manganese (IV) oxide and carbon dioxide:

2MnCO_3(s)+O_2(g)\rightarrow 2MnO_2(s)+2CO_2(g)

In the second step, manganese (IV) oxide and aluminum react to form manganese and aluminum oxide:

3MnO_2(s)+4Al(s)\rightarrow 3Mn(s)+2Al_2O_3(s)

Write the net chemical equation for the production of manganese from manganese (II) carbonate, oxygen and aluminum. Be sure your equation is balanced.

Answer : The net chemical equation for the production of manganese is:

6MnCO_3(s)+3O_2(g)+8Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)

Explanation :

The given two chemical reactions are:

(1) 2MnCO_3(s)+O_2(g)\rightarrow 2MnO_2(s)+2CO_2(g)

(2) 3MnO_2(s)+4Al(s)\rightarrow 3Mn(s)+2Al_2O_3(s)

First we are multiplying reaction 1 by 3, and reaction 2 by 2, we get:

(1)

(2) 6MnO_2(s)+8Al(s)\rightarrow 6Mn(s)+4Al_2O_3(s)

Now we are adding both the reactions, we get the overall chemical reaction.

6MnCO_3(s)+3O_2(g)+6MnO_2(s)+8Al(s)\rightarrow 6MnO_2(s)+6CO_2(g)+6Mn(s)+4Al_2O_3(s)

The  MnO_2 is common on both side, by cancelling it, we get:

The net chemical equation for the production of manganese is:

6MnCO_3(s)+3O_2(g)+8Al(s)\rightarrow 6CO_2(g)+6Mn(s)+4Al_2O_3(s)

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Calculate the number of atoms of each element. 2,6,15,3,8,5?
katen-ka-za [31]

Answer:

P 6 atoms

O 15 atoms

Explanation:

P = 2×3= 6

O = 5×3= 15

6 0
2 years ago
Which of the following is not a statement of Dalton's atomic theory of matter?a. Elements are made of atomsb. Atoms of a given e
Alona [7]

Answer:

c. The atoms of one element can be identical to the atoms of another element.

Explanation:

<em>Which of the following is not a statement of Dalton's atomic theory of matter?</em>

<em>a. Elements are made of atoms.</em> TRUE. An atom is the smallest particle of a chemical element that can exist.

<em>b. Atoms of a given element are identical.</em> TRUE. The only slight difference is in the mass of isotopes.

<em>c. The atoms of one element can be identical to the atoms of another element.</em> FALSE. The atoms of different elements are different from one to another.

<em>d. A given compound always has the same number and kinds of atoms. </em>TRUE. This is known as Dalton's law of constant composition.

3 0
3 years ago
Two substances with empirical formula HNO are hyponitrous acid (M = 62.04 g/mol) and nitroxyl (M = 31.02 g/mol).(c) Predict the
Levart [38]

While Nitroxyl, or HNO, has a dihedral form and just one nitrogen, Hyponitrous Acid, N2(OH)2, has both cis and trans structures and contains two nitrogens.

Hyponitrous acid has the chemical formula H2N2O2 or HON=NOH. 62.028 g/mol is the molecular weight of it. Additionally, it can take either a trans or cis form. When dry, the trans-hyponitrous acid crystallizes into white, explosive particles. Recent research has focused on nitroxyl (HNO), the one-electron reduced and protonated congener of nitric oxide (NO), as a potential drug for the treatment of heart failure and as a pre-conditioning agent to prevent ischemia-reperfusion injury, among other potential uses.

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5 0
1 year ago
PLEASE HELP!!
sp2606 [1]
Inbox me for the answer

6 0
2 years ago
calculate the mols of alt gas if the volume is 0.97 liters at a temperature of 12 C and the pressure is 152 Kpa’s
katrin2010 [14]

Answer:

0.062mol

Explanation:

Using ideal gas law as follows;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821Latm/molK)

T = temperature (K)

Based on the information provided;

P = 152 Kpa = 152/101 = 1.50atm

V = 0.97L

n = ?

T = 12°C = 12 + 273 = 285K

Using PV = nRT

n = PV/RT

n = (1.5 × 0.97) ÷ (0.0821 × 285)

n = 1.455 ÷ 23.39

n = 0.062mol

4 0
2 years ago
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