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skad [1K]
2 years ago
12

Which statement is a counterexample to the statement "If x is a prime number, then x is an odd number?"

Mathematics
1 answer:
valentinak56 [21]2 years ago
5 0

Answer:

2

Step-by-step explanation:

2 is a prime number (it can pnly be divided by itself and by one), but it is an even number.

So it's a counterexample of the statement "If x is a prime number, then x is an odd number?"

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BabaBlast [244]
X+y+z=t
simple..
there are no other numbers that we have to follow like (1/2x or 3/4y) so it is just all together=t. the x, y, z will equal t because t is the total number of students taking three languages. And that number should be equivalent to x,y,z combined.

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3 0
3 years ago
Read 2 more answers
In the literal equation below, what do C and F represent?
Zolol [24]
Answer: Variables

F and C are placeholders for numbers. They are called variables because they are allowed to vary, or change. If you change C then it affects F, and vice versa. If the values for the placeholders is not allowed to change, yet it holds a number, then it is considered a constant. In this case, we don't have constants or else the formula isn't too useful. 
3 0
3 years ago
Is 8/15 closest to 0,1/2"or 1
Bumek [7]
8/15 is closest to 1/2
6 0
3 years ago
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aalyn [17]

Answer:

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8 0
3 years ago
prove that the quadrilateral whose vertices are the points A(-1,1), B(-3,4), C(1,5) and D(3,2) is a parallelogram.
Vsevolod [243]

Answer:

Since \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}, then the quadrilateral ABCD is a parallelogram.

Step-by-step explanation:

First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}. If we know that A(x,y) =(-1, 1), B(x,y) =(-3,4), C(x,y) = (1,5) and D(x,y) = (3,2), then the measure of each vector is, respectively:

\overrightarrow{AB} = (-3,4)-(-1,1)

\overrightarrow{AB} = (-2, 3)

\overrightarrow{DC} = (1,5)-(3,2)

\overrightarrow{DC} = ( -2,3)

\overrightarrow{AD} = (3,2)-(-1,1)

\overrightarrow{AD} = (4, 1)

\overrightarrow{BC} = (1,5)-(-3,4)

\overrightarrow{BC} = (4, 1)

Since \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}, then the quadrilateral ABCD is a parallelogram.

7 0
3 years ago
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