The expression 8x3y2z is a A. Monomial B. Binomial C. Trinomial

A real estate company is interested in testing whether the mean time that families in Gotham have been living in their current h

In-s [12.5K]

Answer:

the answer d , the second answer is b, the third answer is b,

Step-by-step explanation:

5 0

3 years ago

Mrs. Crosby had 350 sheets of paper. She used 8 sheets of paper for a craft. She then gave each student 4 sheets of paper. Which

Vera_Pavlovna [14]

B = 2 i had this question

8 0

2 years ago

Which expression is equivalent to (x^1/2y^-1/4z)^-2?

tiny-mole [99]

Answer:

y^1/2/xz^2 option 3

Step-by-step explanation:

(x^1/2 y^-1/4 z)^-2= x^(-1/2*2) y^(1/4*2) z^-2= x^-1 y^1/2 z^-2= y^1/2/xz^2

7 0

2 years ago

while shopping for clothes, Tracey spent 38$ less than 3 times what Daniel spent. write and solve an equation to find how much D

alexandr1967 [171]

$\bold{\huge{\orange{\underline{Solution}}}}$

$\bold{\underline{ Given :- }}$

While shopping for clothes Tracey spent 38$ less than 3 times of what Daniel spent

$\bold{\underline{ To\: Find :- }}$

We have to determine the total cost spent by daniel

$\bold{\underline{ Let's \: Begin :- }}$

Cost spent by Tracey for her clothes = 38$

Let assume the spending by Daniel is x

$\bold{\underline{Therefore ,}}$

$\sf{ x / 3 = 38 }$

$\sf{ x = 38 × 3 }$

$\sf{ x = 114 dollar }$

$\sf{\red{ Hence,\: Daniel\: spent\: 114 \: dollars\: on \: His\: clothes }}$

7 0

2 years ago

kicyunya [14]

Answer:

8.69% probability that at least 285 rooms will be occupied.

Step-by-step explanation:

For each booked hotel room, there are only two possible outcomes. Either there is a cancelation, or there is not. So we use concepts of the binomial probability distribution to solve this question.

However, we are working with a big sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

A popular resort hotel has 300 rooms and is usually fully booked. This means that $n = 300$

About 7% of the time a reservation is canceled before the 6:00 p.m. deadline with no pen-alty. What is the probability that at least 285 rooms will be occupied?

Here a success is a reservation not being canceled. There is a 7% probability that a reservation is canceled, and a 100 - 7 = 93% probability that a reservation is not canceled, that is, a room is occupied. So we use $p = 0.93$