13) (-2. – 5v).- (-4v – 2) Can you help a girl out
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Fun. I prefer Oxymetazoline.
For the control group we have a headache probability of
c = 368/1671 = .220
For the experimental group we have a headache probability of
e = 494/2013 = .245
The observed difference is
d = e - c = .025
The variance of the difference is
s² = c(1-c)/n₁ + e(1-e)/n₂
so the standard deviation is
We get a t statistic on the difference of
t = d/s = .025/.0139 = 1.79
We're interested in the one sided test, P(d > 0). We have enough dfs to assume normality. We look up in the standard normal table
P(z < 1.79) = .96327
so
p = P(z > 1.79) = 1 - .96327 = 0.037 = 3.7%
Answer: That's less that 10% so we have evidence to conclude that headaches are significantly greater in the experimental group.
Answer: The required number of large order of chicken tenders is 5.
Step-by-step explanation: Given that Sheila loves to eat chicken tenders. A small order comes with 5 chicken tenders, and a large order comes with 8 chicken tenders.
Last month, Sheila ordered chicken tenders a total of 7 times. She received a total of 50 chicken tenders.
We are to find the number of large chicken tenders received by Sheila.
Let x and y represents the number of small orders and large orders respectively of chicken tenders.
Then, according to the given information, we have
and
Thus, the required number of large order of chicken tenders is 5.