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sertanlavr [38]
3 years ago
8

50b + 3f = 27 (b + f = 16) How do you solve b and f?

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

b= −3 /50 f+ 27/ 50

f= −50 /3 b+9

Step-by-step explanation:

Let's solve for <em>b</em>.

50b+3f=27

Step 1: Add -3f to both sides.

50b+3f+−3f=27+−3f

50b=−3f+27

Step 2: Divide both sides by 50.

50b /50 = −3f+27 /50 b= −3 /50 f+ 27 /50

Let's solve for <em>f</em>.

50b+3f=27

Step 1: Add -50b to both sides.

50b+3f+−50b=27+−50b

3f=−50b+27

Step 2: Divide both sides by 3.

3f /3 = −50b+27 /3

f= −50 /3 b+9

brainliest please?

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Read 2 more answers
Use &lt;, &gt;, or = to compare the following decimals.
Alina [70]

Answer:

A) is <

b) is =

c) is <

Step-by-step explanation:

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2 years ago
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Vlada [557]

Answer:

x^2 -20x + 100

Step-by-step explanation:

How this works is that you multiply each number by every other number, so.

(x+a)(x+b) so you do x times x since the parenthesis multiplies them together. Then you do x times b.

Then you do a times x since a is the next number in the first pair. then you do a times b.

(* is the sign for multiplication for the sake of simplifying it and to be easier than doing something like x x x where you are multiplying x together with x.)

So in the expression (x + a)(x + b) you are basically doing

x * x            +         x * b           +        a * x        +          a * b

In your case, a is = to -10 and b is equal to -10

So your expression would be

x * x    +   x * -10    +    -10 * x     +    -10 * -10

so x times x is x^2 and x times -10 is -10x     You are doing -10 * x twice so it is -20x and -10 times -10 is 100

So the final equation would be x^2 plus -20x plus 100 or

x^2 + (-20x)  + 100

which is

x^2 -20x + 100

Hope this helps!

4 0
2 years ago
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