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sertanlavr [38]
3 years ago
8

50b + 3f = 27 (b + f = 16) How do you solve b and f?

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

b= −3 /50 f+ 27/ 50

f= −50 /3 b+9

Step-by-step explanation:

Let's solve for <em>b</em>.

50b+3f=27

Step 1: Add -3f to both sides.

50b+3f+−3f=27+−3f

50b=−3f+27

Step 2: Divide both sides by 50.

50b /50 = −3f+27 /50 b= −3 /50 f+ 27 /50

Let's solve for <em>f</em>.

50b+3f=27

Step 1: Add -50b to both sides.

50b+3f+−50b=27+−50b

3f=−50b+27

Step 2: Divide both sides by 3.

3f /3 = −50b+27 /3

f= −50 /3 b+9

brainliest please?

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Nataly_w [17]
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The weights of 40 students were recorded. If the 75th percentile of
RUDIKE [14]
In the given question, there are numerous information's already provided. It is important to note then down first. With the help of those given information's the required answer can be easily reached.
Percentage of students that weighed 140 pounds = 75 percent
Then
Percentage of students that weighed more than 140 pounds = (100 - 75) percent
                                                                                                  = 25 percent
Total number of students that were weighed = 40 students
Total number of students that weighed more than 140 pounds = (25/100) * 40
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So the number of students that weighed more than 140 pounds is 10. So the correct option in regards to the given question is option "1".
7 0
3 years ago
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