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QveST [7]
3 years ago
11

A right triangle has a side with length 12 in and a hypotenuse with length 20 in. find the length of the second leg (in inches).

(round to the nearest hundredth if needed)
Mathematics
1 answer:
Kipish [7]3 years ago
7 0
If the second leg is x so
 x² = b² - a²
x² = (20)² - (12)² = 256
x = 16 in
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x= -10

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3 years ago
Can I please get some help with this :D
Luba_88 [7]
1. Anwser=53.3 (do 40*3 then anwser x 4)
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6 0
2 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
Find the value of x. If​ necessary, write your answer in simplest radical form. 30 x 25 x nothing ​(Simplify your answer. Type a
murzikaleks [220]

Answer:

x = 38.05

Step-by-step explanation:

Using the Pythagoras theorem to find x

x is the hypotenuse

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x² = 30²+25²

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x² = 1525

x = √1525

x = 39.05

4 0
3 years ago
How do I get this equation to equal 130 by putting parentheses in it...310-20÷2×5+13
elena-14-01-66 [18.8K]
The correct is 283 maybe
8 0
3 years ago
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