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oee [108]
3 years ago
5

Use the value of the linear correlation coefficient r to find the coefficient of determination and the percentage ofthe total va

riation that can be explained by the linear relationship between the two variables. r = 0.885 (x = weight of male, y = waist size of male)
Mathematics
1 answer:
Vikentia [17]3 years ago
4 0

Answer:

Step-by-step explanation:

The coefficient of determination = r^{2}  = 0.885^{2} = 0.7832

It means about 78% variation in waist size of males can be explained by their weight and about 23% can not be explained.

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A rectangular field is twice as long as it is wide. if the perimeter of the field is 450 yards. what are the fields dimensions?
Nat2105 [25]
Let width = x
let length = 2x
x + 2x = 450
3x = 450
x = 150
width = 150
length = 2x = 2 (150) = 300
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Bill is selling stickers to raise money for a charity. He sold 36 stickers on the first day and 23 on the second day. He had 26
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Last HW Mr Thompson! Please Help!
TiliK225 [7]

Answer:

B, D, D, B, C

Step-by-step explanation:

1) The part of the equation that tells us the graph would open downward would be B, the negative coefficient of x^{2}.

We know this because, if we reorganize the equation into the standard form  y = mx + b, we get y = -(x²) + 1. This means that for any value we substitute for x, y will always be negative. The answer is B.

2) To find the zeroes of this function, we just have to see which answer makes the function, well, zero.

We have the equation y = (-16t - 2) (t - 1)

We set the equation equal to zero like this:

0 = (-16t - 2) (t - 1)

We also know that anything multiplied <em>by</em> zero will <em>equal</em> zero, so:

0 = (-16t - 2) and 0 = (t - 1)

Now we just solve for t in both equations:

0 = -16t - 2

-16t = 2

t = 2/-16 or -1/8

0 = t - 1

t = 1

So our answer will be D.

3) This time, we are given the same equation but the variable t represents time and y represents the height.

The zeroes are when y = 0, so the zeroes (which are 1 and -1/8 from the last problem) mean that the height is also at zero (which is the ground).

Furthermore, time cannot be negative, so the correct answer choice would be D.

4) We are given the same equation and story problem, but instead we are asked to find the height when the ball was thrown. In other words, we need to find the y-intercept.

The y-intercept is when t = 0, so:

y = (-16t - 2) (t - 1)

y = (-16(0) - 2) (0 - 1)

y = (-2) (-1)

y = 2

So, the correct answer is B, 2 feet.

5) This problem is a simple theoretical question. We know that the constant c will represent the vertical translation or y-intercept, so the correct answer is C.

8 0
3 years ago
Make x the subject of y=alog(5x)
Bond [772]

Answer:

x = 0.2(10^y/a).

Step-by-step explanation:

y = alog(5x)

y = log(5x)^a)   By the definition of a log:

(5x)^a  = 10^y

5x = (10^y) ^ 1/a

x = 0.2(10^y/a)

4 0
3 years ago
Which points on the curve of x^2 - xy - y^2 = 5 have vertical tangent lines?
algol [13]

We need to differentiate this with respect to x to see if we can find an expression for the derivative of y at various points.  That will be the slope of the tangent to the curve.  Then we want to see where that derivative might be infinite -- i.e., where the tangent is vertical.

 

It's not written as a function, but it can still be differentiated using the chain rule:

 

x2 + xy + y2 = 3

(2x) + (x dy/dx + y dx/dx) + (2y dy/dx) = 0

 

(I used parentheses to show the differentiation of each term in the original equation.)

 

2x + x dy/dx + y + 2y dy/dx = 0

2x + y = -x dy/dx - 2y dy/dx

2x + y = dy/dx (-x -2y)

-(2x + y)/(x + 2y) = dy/dx

 

We have the derivative of y, but it's defined partly in terms of y itself.  That's OK.  Let's go on...

 

So where would the slope be infinite?  That would happen when x + 2y = 0, or y = -x/2

 

Let's plug that in for y in the original equation to find points where that's the case.

 

x2 + xy + y2 = 3

x2 + x(-x/2) + (-x/2)2 = 3

x2 - x2/2 + x2/4 = 3

3x2 / 4 = 3

x2 = 4

x = ±2

 

So we have two x values where the tangent might be vertical.  Let's plug them into the equation and see what the y values are.  First x = 2...

 

x2 + xy + y2 = 3

4 + 2y + y2 = 3

y2 + 2y + 1 = 0

(y + 1)2 = 0

y = -1

 

So at the point (2, -1) the tangent is vertical.

 

Now try x = -2...

 

x2 + xy + y2 = 3

4 - 2y + y2 = 3

y2 - 2y + 1 =0

(y - 1)2 = 0

y = 1

 

So at the point (-2, 1) the tangent is vertical.

8 0
3 years ago
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