Answer:
Costa Rica
Step-by-step explanation:
Answer:
no solutions
Step-by-step explanation:
Hi there!
We're given this system of equations:
x+y=3
4y=-4x-4
and we need to solve it (find the point where the lines intersect, as these are linear equations)
let's solve this system by substitution, where we will set one variable equal to an expression containing the other variable, substitute that expression to solve for the variable the expression contains, and then use the value of the solved variable to find the value of the first variable
we'll use the second equation (4y=-4x-4), as there is already only one variable on one side of the equation. Every number is multiplied by 4, so we'll divide both sides by 4
y=-x-1
now we have y set as an expression containing x
substitute -x-1 as y in x+y=3 to solve for x
x+-x-1=3
combine like terms
-1=3
This statement is untrue, meaning that the lines x+y=3 and 4y=-4x-4 won't intersect.
Therefore the answer is no solutions
Hope this helps! :)
The graph below shows the two equations graphed; they are parallel, which means they will never intersect. If they don't intersect, there's no common solution
Using the expected value, it is found that the mean of the distribution equals $0.1.
- The expected value, which is the mean of the distribution, is given by <u>each outcome multiplied by it's probability</u>.
The probabilities of <u>each outcome</u> are:
- .0000001 probability of earning $1,000,000.
- .9999999 probability of earning $0.
Thus, the mean is given by:

Thus showing that the expected value is $0.1.
A similar problem is given at brainly.com/question/24855677
Answer:
What's the picture?
If you provide the picture of the graph I can help