All categories

3 years ago

Given ⊙A, an angle ∠CDB is inscribed with ∡CDB=43°. A second angle, ∠CEB, is inscribed. Find ∡CEB.

Mathematics

1 answer:

wel3 years ago

5 0

180 Fosho Fosho I think

You might be interested in

Can someone help me Thank you

Mazyrski [523]

Okay. Let’s begin!

I order to solve this problem we must u do it and redo it. We have to find the diameter and the radius

Step one: 15 divided by 3.14 (PI) which is 4.77707006. That’s the diameter. Now divide that by two for the radius which is 2.38853503

Step two: find the area

Formula: PI(r)^2

Step three: solve for the area

3.14(2.38853503)^2

Step four: answer

Your answer is.....

17.9140127. Or if ur rounding:

18.

I hope this helped!

4 0

3 years ago

500% of what number is 4350

eimsori [14]

Answer:

Percentage Calculator: 430 is what percent of 500? = 86.

5 0

3 years ago

Evaluate P = 50x + 80y at each vertex of the feasible region. (0, 0) P = (0, 15) P = (6, 12) P =

Yanka [14]

(0, 0) P = ⇒ 0

(0, 15) P = ⇒ 1200

(6, 12) P = ⇒ 1260

4 0

4 years ago

Read 2 more answers

What is the resistance of a 1.00X10^2 -Ω , a 2.50-kΩ , and a 4.00-k Ω resistor connected in parallel?

Andreas93 [3]

Answer:

Therefore, the total Resistance: R = 93.9 Ω

Step-by-step explanation:

Given

R₁ = 1 × 10²

R₂ = 2.5 kΩ = 2.5 × 10³ Ω

R₃ = 4 kΩ = 4 × 10³ Ω

Given that the given resisters are connected parallel, so using the formula to calculate the total Resistance R:

$\frac{1}{R}\:=\:\frac{1}{R_1}\:+\:\frac{1}{R_2}+\frac{1}{R_3}$

susbtituting R₁ = 1 × 10², R₂ = 2.5 × 10³ Ω, and R₃ = 4 × 10³ Ω

$\frac{1}{R}=\frac{1}{1\times \:10^2}+\frac{1}{2.5\times \:10^3}+\frac{1}{4\times \:10^3}$

Multiply by LCM of R, 100, 2500, and 4000: 20000 R

$\frac{1}{R}\cdot \:20000R=\frac{1}{1\cdot \:10^2}\cdot \:20000R+\frac{1}{2.5\cdot \:10^3}\cdot \:20000R+\frac{1}{4\cdot \:10^3}\cdot \:20000R$

simplify

$20000=213R$

Switch sides

$213R=20000$

Divide both sides by 213

$\frac{213R}{213}=\frac{20000}{213}$

Simplify

$R=\frac{20000}{213}$

$R = 93.9$ Ω

Therefore, the total Resistance: R = 93.9 Ω

4 0

3 years ago

Will give brainliest please help asap

Gemiola [76]

Your answer D. 8 is right; this is $log_{4}$ 64, which we know is 3 because 4^3 is 64.
---
Hope this helps!
==jding713==

7 0

3 years ago