let's firstly convert the mixed fractions to improper fractions and then to do away with the denominators, let's multiply both sides by the LCD of all denominators.
![\stackrel{mixed}{1\frac{3}{4}}\implies \cfrac{1\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{7}{4}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{7}{4}-\cfrac{4}{5}=\cfrac{35}{20}-\boxed{?}\implies \stackrel{\textit{multipling both sides by }\stackrel{LCD}{20}}{20\left( \cfrac{7}{4}-\cfrac{4}{5} \right)=20\left( \cfrac{35}{20}-\boxed{?} \right)} \\\\\\ 35-16=35-20\boxed{?}\implies 19=35-20\boxed{?}\implies -16=-20\boxed{?} \\\\\\ \cfrac{-16}{-20}=\boxed{?}\implies \cfrac{4}{5}=\boxed{?}](https://tex.z-dn.net/?f=%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%204%2B3%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B7%7D%7B4%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B7%7D%7B4%7D-%5Ccfrac%7B4%7D%7B5%7D%3D%5Ccfrac%7B35%7D%7B20%7D-%5Cboxed%7B%3F%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultipling%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B20%7D%7D%7B20%5Cleft%28%20%5Ccfrac%7B7%7D%7B4%7D-%5Ccfrac%7B4%7D%7B5%7D%20%5Cright%29%3D20%5Cleft%28%20%5Ccfrac%7B35%7D%7B20%7D-%5Cboxed%7B%3F%7D%20%5Cright%29%7D%20%5C%5C%5C%5C%5C%5C%2035-16%3D35-20%5Cboxed%7B%3F%7D%5Cimplies%2019%3D35-20%5Cboxed%7B%3F%7D%5Cimplies%20-16%3D-20%5Cboxed%7B%3F%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B-16%7D%7B-20%7D%3D%5Cboxed%7B%3F%7D%5Cimplies%20%5Ccfrac%7B4%7D%7B5%7D%3D%5Cboxed%7B%3F%7D)
Answer: m=1
Step-by-step explanation:
Use the equation y=y2-y1 over x2-x1
1. label your points
0=x1
-2=y1
-3=x2
-5=y2
The first pair is x1 and y1 and the next pair is x2 and y2
plug in the numbers to find your answer
Edited answer: The number is: "- 6" .
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8 (8 + x) = 16 ;
in which "x" represents the number for which to be solved ;
8*8 + 8*x = 16 .
Edit: 64 + 8x = 16 ;
Subtract "64" from each side of the equation:
Edit: 64 + 8x − 64 = 16 <span>− 64 ;
to get: 8x = </span>- 48 ;
Divide EACH SIDE of the equation by "8" ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ;
Edit: 8x / 8 = -48 / 8 ;
Edit: x = - 6 .
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The number is: "- 6" .
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Let us check our answer, by plugging in "-6" for "x" in the original equation:
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8 (8 + x) = 16 ;
→ 8 [8 + (-6) ] =? 16 ?? ;
→ 8 (8 − 6 ) =? 16 ?? ;
→ 8 (2) =? 16 ?? ;
→ 16 = ? 16 ?? Yes!
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Y=|x-7| because in order to go to the right you have to subtract the amount from x
