Answer:
(E)-3-hexene treated with bromine to form racemic mixture.
Explanation:
(E)-3-hexene treated with bromine to form (S)−3−bromohexane and (R)−3−bromohexane.
The chemical reaction is as follows.
Answer:
moles react.
Explanation:
In a chemical reaction equation, we know that chemical species react in moles. It is actually the moles of the individual chemical species that participate in a chemical reaction and not the masses of those species.
In solving stoichiometric problems, it is mandatory to use moles as a conversion factor in calculating the mass of product formed or the mass of reactant consumed. We often read off the number of moles that reacted from the balanced reaction equation and then convert the reacting mass of species given to the number of moles of that specie that actually participated in the reaction in order to obtain any required information from a reaction.
Answer:
The best reagents that are used for the conversion of ethylbenzene to (2-bromoethyl)benzene is shown in the first diagram attached.
Explanation:
Concepts and reason
The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.
Here, the starting reactant is ethyl benzene and the final product is (2-bromoethyl)benzene.
Fundamentals
Bromine molecule is used for bromination of alkene. Trans addition takes place.
Addition of HBr to the double bond forms an alkyl bromide.
Potassium tertiary butoxide is a sterically hindered base.
Bromination of alkane in the presence of sunlight gives radical substitution.
NBS (N-bromosuccinimide) is used for the allylic bromination.
The reaction is as shown in the second attachment(pictures 2,3 and 4).