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lapo4ka [179]
3 years ago
9

Please help me I’m very bad at math and I’m goibn thru it

Mathematics
2 answers:
vodomira [7]3 years ago
5 0

The answer is in the picture provided below. :)

Natali [406]3 years ago
4 0
2(4+x)

Distribute the 2 onto the 4 and x

2*4 = 8
2*x = 2x
—————
2x+8
—————
To evaluate, do 2x+8=0 (isolate x)

Subtract 8 on both sides

2x=-8

Divide by 2

X=-4

I hope I helped you out :)
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One bag contains 3/5 kg of corn. A farmer feeds his chickens 4 bags of corn each week. How many kilograms of corn do they eat ea
Svet_ta [14]
1day=\frac{1}{7}week\\\\4\ bags\ for\ 1\ week\\
x\ bags\ for\ \frac{1}{7}\ week\\\\
cross\ multipliction:\\
4*\frac{1}{7}=x\\
x=\frac{4}{7}\\\\
In\ one\ bag\ there\ is\ \frac{3}{5}kg\ of\ corn\\
In\ \frac{4}{7}\ of\ bag\ there\ is:\\
\frac{4}{7}*\frac{3}{5}kg=\frac{12}{35}kg\\\\
He \ need\ \frac{12}{35}kg\ of\ corn\ each\ day.

3 0
3 years ago
5th grade math. correct answer will be marked brainliest.
Mrac [35]

Answer:

5 11/24 fluid ounces of dressing remains in the jar

7 0
3 years ago
The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?
Mnenie [13.5K]

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

133.34g = 6.023*10^2^3

If we equate this

133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

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5 0
2 years ago
I dont understand the graphic ​
MrRa [10]

Answer:

do you want me to explain what the graph is showing or give you the answer

5 0
3 years ago
A submarine is diving to a total depth of 45 feet. It descends 15% of the total depth in 1 minute. How deep will the submarine b
miss Akunina [59]
15% of 45 is 0.15 x 45 or 6.75 feet.  That's how far the submarine descended in 1 minute.  So, in 4 minutes the submarine would be 4 x 6.75 feet down which is 27 feet.
8 0
3 years ago
Read 2 more answers
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