3 years ago

Need help on this please

Mathematics

1 answer:

jek_recluse [69]3 years ago

5 0

The circumference should be 37.69911.

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Leo has had test scores of 85, 92 and 87. He has one test left. What test score t must he to average at least a 90 for his four

LenKa [72]

96

The mean of 85+92+87+96=90

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3 years ago

Order these decimals greatest to least 0.2 ; -0.4 ; -4.5

Mice21 [21]

0.2,
-0.4,
-4.5
hope this helps

6 0

3 years ago

Masja [62]

Answer:

60 units

Step-by-step explanation:

Ratio of the perimeter = ratio of sides

Sides are in the ratio:

6 : 24

1 : 4

Perimeter of the first triangle:

4+5+6 = 15

Perimeter of the second triangle:

4(15) = 60

6 0

4 years ago

Given square ABCD, with point P on side AB , point Q on side BC, point R on side CD, and point S on side DA as shown. Additional

sveta [45]

The ratio of the area of square PQRS to the area of square ABCD is 5/9

<h3>Area of square ABCD</h3>

Assume the measure of the side lengths of the square ABCD is 1, then the area of the square ABCD is:

$A_1 = 1 \times 1$

$A_1 = 1$

See attachment for the diagram that represents the relationship between both squares.

<h3 /><h3>Pythagoras theorem</h3>

The measure of length PQ is then calculated using the following Pythagoras theorem:

$PQ^2 = (\frac 13)^2 + (\frac 23)^2$

Evaluate the squares

$PQ^2 =\frac 19 + \frac 49$

Add the fractions

$PQ^2 =\frac 59$

<h3>Area of square PQRS</h3>

The above represents the area of the square PQRS.

i.e.

$A_2 =\frac 59$

So, the ratio of the area of PQRS to ABCD is:

$Ratio = \frac{A_2}{A_1}$

This gives

$Ratio = \frac{5/9}{1}$

$Ratio = \frac{5}{9}$

Hence, the ratio of the area of square PQRS to the area of square ABCD is 5/9