this can be solve using newtons heating of cooling
(Ts – T) =(Ts – To)*e^(-kt)
Where Ts is the ambient temperature
To is initial temperature
T is the temperature at time t
t is the time
k is constant
fisrt solve the constant k for the given first scenario
(99 – 36) = (99 – 46)*e(-5k)
K = -0.0346
Using k, solve T at t = 13 min
(99 – 46) = (99 – T)*e(-13*(-0.0346)
T = 58.82 degree F
Answer:
15.4
Step-by-step explanation:
-5×(-4.9) +7×(-1.3)
=24.5+(-9.1)
=24.5-9.1
==15.4
Answer:
The speed from the observer is 8 mph.
Step-by-step explanation:
When the boat is going downstream with full force, its speed will be the one the oarsman can row on still water added by the flow of the river. In this case he can row the boat at speed of 3 mph, while the stream is 5 mph, so the speed from the observer standpoint is:
The speed from the observer is 8 mph.
Answer:
enlargement and the scale factor is 6.4 feet per inch
Step-by-step explanation:
Answer:
1=163 degrees
2=×=10 degrees
3=×=3
Step-by-step explanation:
54x+1+9x-10=180 we are using this expression because alternate angles add up to 180 degrees
54x+9x+1-10=180
63x-9=180
63×=180+9
63×=189
63×÷63×=189÷63×
X=3
Angle in bold print is (54x+1)
54×3=162
162+1=163 degrees
No.2 Find x
7x+35+x+65 =180
7x+x+35×65=180
8x+100=180
8x=180-100
8x=80
8x÷8x=80÷8
X=10 degrees
No.3 Find x
54x+1+9x-10=180
54x+9x+1-10=180
63x-9=180
63x=180+9
63x=189
63x÷63x=189÷63
X=3
I hope I was of help
