Answer:
y=0.5x + 5
Step-by-step explanation:
The points are (0,5) and (-10,0)
to find the slope do
0-5/-10-0 = 5/10 = 1/2 = 0.5
next plug one of the points into point slope formula
y-y1=m(x-x1)
lets use the point (-10,0)
y1=0
x1= -10
m= 0.5
y-0=0.5(x- -10)
y = 0.5(x+10)
distribute the 0.5
y=0.5x+5
Posting screenshot of my answer in the linked question in case it gets deleted.
THEOREM:
- h² = p² + b² where h is hypotenuse, b is base and p is perpendicular.
ANSWER:
[3] By pythagorean theorem,
- x² = 14² + 9²
- x² = 196 + 81
- x² = 277
- x = √277
- x = 16.64 rounded.
[4] By pythagorean theorem,
- x² = 32² + 24²
- x² = 1024 + 576
- x² = 1600
- x = √1600
- x = 40.
[5] By pythagorean theorem,
- (2x)² = 21² – 12.6²
- 4x² = 441 – 158.76
- 4x² = 284.24
- x² = 284.24/4 = 70.56
- x = √70.56
- x = 8.4
[6] By tangent property,
- 7x – 29 = 2x + 16
- 7x – 2x = 16 + 29
- 5x = 45
- x = 9.
So, WX = 7(9) – 29 = 63 – 29
Answer:
60
Step-by-step explanation:
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Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.