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storchak [24]
2 years ago
8

Find the exact value of tan 60° in simplest form with a rational denominator.​

Mathematics
1 answer:
Elis [28]2 years ago
3 0

Step-by-step explanation:

We need to find the exact value of tan 60° in simplest form with a rational denominator.​

We know that, \tan\theta=\dfrac{\sin \theta}{\cos\theta}

Here, \theta=60^{\circ}

So,

\tan(60)=\dfrac{\sin (60)}{\cos(60)}\\\\=\dfrac{\dfrac{\sqrt3}{2}}{\dfrac{1}{2}}\\\\=1.73\\\\or\\\\=\dfrac{173}{100}

Hence, this is the required solution.

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−2x=x^2−6
Iteru [2.4K]

Step-by-step explanation:

Example 1

Solve the equation x3 − 3x2 – 2x + 4 = 0

We put the numbers that are factors of 4 into the equation to see if any of them are correct.

f(1) = 13 − 3×12 – 2×1 + 4 = 0 1 is a solution

f(−1) = (−1)3 − 3×(−1)2 – 2×(−1) + 4 = 2

f(2) = 23 − 3×22 – 2×2 + 4 = −4

f(−2) = (−2)3 − 3×(−2)2 – 2×(−2) + 4 = −12

f(4) = 43 − 3×42 – 2×4 + 4 = 12

f(−4) = (−4)3 − 3×(−4)2 – 2×(−4) + 4 = −100

The only integer solution is x = 1. When we have found one solution we don’t really need to test any other numbers because we can now solve the equation by dividing by (x − 1) and trying to solve the quadratic we get from the division.

Now we can factorise our expression as follows:

x3 − 3x2 – 2x + 4 = (x − 1)(x2 − 2x − 4) = 0

It now remains for us to solve the quadratic equation.

x2 − 2x − 4 = 0

We use the formula for quadratics with a = 1, b = −2 and c = −4.

We have now found all three solutions of the equation x3 − 3x2 – 2x + 4 = 0. They are: eftirfarandi:

x = 1

x = 1 + Ö5

x = 1 − Ö5

Example 2

We can easily use the same method to solve a fourth degree equation or equations of a still higher degree. Solve the equation f(x) = x4 − x3 − 5x2 + 3x + 2 = 0.

First we find the integer factors of the constant term, 2. The integer factors of 2 are ±1 and ±2.

f(1) = 14 − 13 − 5×12 + 3×1 + 2 = 0 1 is a solution

f(−1) = (−1)4 − (−1)3 − 5×(−1)2 + 3×(−1) + 2 = −4

f(2) = 24 − 23 − 5×22 + 3×2 + 2 = −4

f(−2) = (−2)4 − (−2)3 − 5×(−2)2 + 3×(−2) + 2 = 0 we have found a second solution.

The two solutions we have found 1 and −2 mean that we can divide by x − 1 and x + 2 and there will be no remainder. We’ll do this in two steps.

First divide by x + 2

Now divide the resulting cubic factor by x − 1.

We have now factorised

f(x) = x4 − x3 − 5x2 + 3x + 2 into

f(x) = (x + 2)(x − 1)(x2 − 2x − 1) and it only remains to solve the quadratic equation

x2 − 2x − 1 = 0. We use the formula with a = 1, b = −2 and c = −1.

Now we have found a total of four solutions. They are:

x = 1

x = −2

x = 1 +

x = 1 −

Sometimes we can solve a third degree equation by bracketing the terms two by two and finding a factor that they have in common.

6 0
3 years ago
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How much would $500 invested at 7% interest compounded continuously be worth after 4 years? Round your answer to the nearest cen
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Hi I hope this helps;

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If julie needs 3 14_ cups of oatmeal, how many 1_ 4 cups of oatmeal will she use?
nydimaria [60]
She will use 13  there are four 1/4 per cup 4 times 3 plus 1 =13
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3 years ago
Pleasee answer this ovo
Liula [17]
ÒvÓ is your answer!!!
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2 years ago
Read 2 more answers
What is the square of 5y?
Virty [35]

Answer:

<h3>25y^2</h3>

Step-by-step explanation:

(5y)^2\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(a\times\:b\right)^n=a^nb^n\\\\\left(5y\right)^2=5^2y^2\\\\5^2=25\\\\=25y^2

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