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storchak [24]
3 years ago
8

Find the exact value of tan 60° in simplest form with a rational denominator.​

Mathematics
1 answer:
Elis [28]3 years ago
3 0

Step-by-step explanation:

We need to find the exact value of tan 60° in simplest form with a rational denominator.​

We know that, \tan\theta=\dfrac{\sin \theta}{\cos\theta}

Here, \theta=60^{\circ}

So,

\tan(60)=\dfrac{\sin (60)}{\cos(60)}\\\\=\dfrac{\dfrac{\sqrt3}{2}}{\dfrac{1}{2}}\\\\=1.73\\\\or\\\\=\dfrac{173}{100}

Hence, this is the required solution.

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Perpendicular bisectors are segment that passes through the mid point of a triangle, while altitude is the perpendicular distance from the base to the opposite vertex.
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What is 16 out of 24 as a grade
Dominik [7]
16 out of 24 would equal around 67%, and that as a grade would be a D.
However, grades MAY vary from school to school.
But on average:
A= 100 through 90, B= 89 through 80, C= 79 through 70, D= 69 through 60, and an F= 59 and below that.
Keep in my mind that if your grade has digits after the decimal, it will be rounded (in your case) and that may also change your grade, for example if your grade is 79.7%, then it will be rounded to 80%, and your grade will be a B.
6 0
3 years ago
Evaluate the value of x to 1 d.p<br><br><br> Thank you
Keith_Richards [23]

Answer:

value of x = 2.8

Step-by-step explanation:

By law of cosines,

{a}^{2}  =  {b}^{2}  +  {c}^{2}   - 2 \times b \times c \times cos(100) \\  {x}^{2}  =  {13}^{2}  +  {10}^{2}  - (2 \times 13 \times 10 \times cos100) \\  = 169 + 100 - 260 \times 0.862 \\  = 269 - 260 \times 0.862 \\  = 7.758 \\x =  \sqrt{7.758 }  \\  = 2.785 \\  = approx \: 2.8

6 0
3 years ago
write the linear equation point slope form for the line that is perpendicular to y = -2x+1 and has (4,2) as a solutien.
ladessa [460]
Subtract 4 from both sides of the equation.

y=-4-2x+2

add -4 and +2.

the answer is

y=-2x-2

7 0
3 years ago
The point-slope form of the equation of a line that passes through points (8,4) and (0, 2) is y-
Oksi-84 [34.3K]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

While the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It's the slope

(x_ {0}, y_ {0}):It is a point through which the line passes

In this case we have a line through:

(8,4) and (0,2)

Therefore, its slope is:

m = \frac {2-4} {0-8} = \frac {-2} {- 8} = \frac {1} {4}

Its point-slope equation is:

y-4 = \frac {1} {4} (x-8)

Then, we manipulate the expression to find the equation of the slope-intersection form:

y-4 = \frac {1} {4} x- \frac {8} {4}\\y-4 = \frac {1} {4} x-2\\y = \frac {1} {4} x-2 + 4\\y = \frac {1} {4} x + 2

Therefore, the cut-off point with the y-axis is b = 2

ANswer:

y = \frac {1} {4} x + 2

7 0
3 years ago
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