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3 years ago

Expand and simplify 2(x+7)+3(x+1)

Mathematics

1 answer:

Digiron [165]3 years ago

4 0

2(x+7)+3(x+1)
= 2x + 14 + 3x + 3
= 5x + 17 Answer

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The vertices of triangle PQR are P(10,-6), Q(6,2), & R(4,-1). Describe a translation that places the image of the triangle e

Gnoma [55]

Answer:

Translate 7 units up and then translate 11 units to the left.

Step-by-step explanation:

We have the triangle PQR having co-ordinates (10,6), (6,2) and (4,-1).

It is required to translate ΔPQR so that the resulting image is completely inside the 2nd quadrant.

So, for that we will apply the following sequence of translations:

1. Translate 7 units up.

This will give us the figure in the 1st quadrant having co-ordinates (10,1), (6,9) and (4,6).

2. Translate 11 units to the left

We will get the final triangle P'Q'R' with the co-ordinates P'(-1,1), Q'(-5,9) and R'(-7,6) as shown below.

5 0

3 years ago

On which number line do the points represent negative five and one over two and +2?

alexandr1967 [171]

Answer:

uh the 2nd one

Step-by-step explanation:

cause im smart

3 0

3 years ago

9 million individuals <br> 4 in 10 are special<br> How many special individuals are there

Ugo [173]

Answer:

SO in 9 million people 3,600,000 are special

Step-by-step explanation:

If 4 in 10 induviduals are special that means that in 10 people, 4 are special and in 20 people 8 are special the pattern here is that to calculate the amount of special induviduals you just multiply (4/10) times that number.

SO for 9 million we get:

$\frac{4}{10} *9,000,000\\=3600000$

7 0

3 years ago

The number of bees spotted in Amelie's garden can also be modeled by the function √ B(x) = 50 k + 2x where x is the daily high t

uranmaximum [27]

Answer:

According to this model, the rate of increase of bees spotted with respect to time when 100 bees are spotted = 80 bees per day.

Step-by-step explanation:

√B(x) = 50 k + 2x

where x is the daily high temperature, in degrees Farenheit.

k is a positive constant.

When the number of bees spotted = 100,

The daily high temperature is increasing at a rate of 2°F per day; (dx/dt) = 2 °F/day

How quickly is the number of bees changing with respect to time when 100 bees are spotted?

√B(x) = 50k + 2x

Taking a time derivative of both sides,

(d/dt) [√B] = (d/dt) [50 k + 2x]

(1/2) (B⁻⁰•⁵) (dB/dt) = (d/dt)(50k) + (d/dt)(2x)

½(B⁻⁰•⁵) (dB/dt) = 50 (dk/dt) + 2 (dx/dt)

B = 100 bees

(dB/dt) = ?

(dk/dt) = 0 (since k is a positive constant)

(dx/dt) = 2°F/day

½(100⁻⁰•⁵) (dB/dt) = 50 (0) + 2 (2)

½(10⁻¹) (dB/dt) = 4

(1/2)(1/10) (dB/dt) = 4

(dB/dt) = 4×2×10 = 80

(dB/dt) = 80 bees per day

Hope this Helps!!!

7 0

3 years ago

Solve for x. x2 - 2x - 24 = 0

Alekssandra [29.7K]

Its false which means it equals to 0 -24=0

7 0

3 years ago

Read 2 more answers