Answer:
- <u>Hannah was not speeding because her speed was about 61 mph, which is below the speed limit.</u>
Explanation:
Just to correct some typos, this is the complete question:
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<em>The equation d=0.05v² + 1.1v models the distance, d, that it takes a car traveling at a speed of v miles per hour to come to a complete stop. If Hannah’s car stopped after travelling 250 feet on a highway with a speed limit of 65 mph, was Hannah speeding? Explain using math whether she was speeding and how you know.</em>
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<h2>Solution</h2>
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To find whether Hannah was speeding, you must find the velocity that is solution for the equation:
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Write it in standard form:
Use the quadratic formula:
The speed can only be positive; thus, it is about 61 miles per hour, which is below the speed limit of 65mph.
In conclusion, she was not speeding.
To do this problem, you need to add together all of the faces!
These are all the faces
A = 8*6
B = 8*6
C = 6*6
D = 6*6
E = 14*6
F = 14*6
G = 14*14 - 8*6
H = 14*14 - 8*6
Adding them all together would get you:
SA = 484 ft^2
I hope this helps!
The crucial part of the wording of the problem tells us that the two integers are consecutive. So, let's call the first term x. Then the other term must be x + 1 since it comes right after it and is an integer. Now we can solve:
x(x + 1) = x + (x + 1) + 19
x^2 + x = 2x + 20
x^2 - x - 20 = 0
Now we factor:
(x - 5)(x + 4) = 0
This means x either equals 5 or x = -4 to satisfy the above equation. We know that x is positive from the question itself, so x must be 5. The number consecutively after it then must be 6.
okay well usually what I would tell you would be to use the ABC method. you would multiply A (2) by C (6) to get twelve. so you need two numbers that multiply to twelve and add to -4 (the B value). but there are no numbers that fit this description so you have to use the GCF method instead
for this method you must find the GCF for all three numbers which in this case is 2. 2(x^2-2x+3) all these numbers are now prime so this is the factored form
