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Dmitry [639]
3 years ago
11

A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t

he height of the big locker what is the total volume of one big locker and one small locker
Mathematics
2 answers:
I am Lyosha [343]3 years ago
7 0

Answer:

Volume of big locker = 0.36 m^{3}

Volume of small locker = 0.18 m^{3}

Total volume = 0.54 m^{3}

Step-by-step explanation:

We are given the following:

Width of larger locker = 0.5 m

Depth of larger locker = 0.6 m

Height of larger locker = 1.2 m

It is a cuboid like structure and it is well known that Volume of a cuboid structure = \text{width} \times \text{depth} \times \text{height}

So, volume of larger locker =

0.5 \times 0.6 \times 1.2\\\Rightarrow .36m^{3}

Width of smaller locker = 0.5 m

Depth of smaller locker = 0.6 m

Height of smaller locker = \dfrac{1.2}{2} = 0.6m

Volume of a cuboid structure = \text{width} \times \text{depth} \times \text{height}

So, volume of smaller locker =

0.5 \times 0.6 \times 0.6\\\Rightarrow 0.18m^{3}

Adding both the volumes, Total volume = 0.54 m^{3}

Tomtit [17]3 years ago
4 0

Answer:

0.54\,\,m^3

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × \frac{1.2}{2}=0.6\,\,m (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= 0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6

=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3

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3 years ago
a car travels along a straight road heading east for one hour, then traveling for 30 minutes on another road that leads northeas
My name is Ann [436]

Answer:

55.96 miles

Step-by-step explanation:

Distance = Speed X time

Car first moved east for 1 hr , distance = 40 x 1 = 40 miles

Car then moved north-east for 30 min, distance = 40 x 0.5 = 20 miles

From trigonometry,

sin 45 = \frac{y}{20} ; y = 20 sin 45 ; y= 14.14 miles

cos 45 = \frac{x}{20} ; x = 20 cos 45 ; x = 14.14 miles

using Pythagoras theorem;

z^{2} = y^{2} + (40+x)^{2}

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6 0
3 years ago
The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho
lyudmila [28]

Answer:

  • <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>

Explanation:

<u>Rewrite the table and the choices for better understanding:</u>

<em>Enrollment at a Technical School </em>

Year (x)       First Year f(x)      Second Year s(x)

2009                  785                        756

2010                   740                        785

2011                    690                        710

2012                   732                         732

2013                   781                          755

Which of the following statements is true based on the data in the table?

  • The solution to f(x) = s(x) is x = 2012.
  • The solution to f(x) = s(x) is x = 732.
  • The solution to f(x) = s(x) is x = 2011.
  • The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>

Thus, the correct choice is the third one:

  • The solution to f(x) = s(x) is x = 2012.
5 0
3 years ago
The radius of the larger circle is 10 cm. The radius of the smaller circle is 3 cm. What is the approximate area of the shaded r
romanna [79]
I just took the test the correct answer is 285.74 square centimeters 
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3 years ago
?<br><br>2 to the 3rd power - 5 x (6 + 4) ÷ 2<br><br>show your work​
Delvig [45]

Answer:

-17

Step-by-step explanation:

2^3 - 5 * (6 + 4) ÷ 2

Following PEMDAS, we must focus on the parenthesis first.

2^3 - 5 * (6 + 4) ÷ 2

2^3 - 5 * (10) ÷ 2

Now we will focus on the exponent:

2^3 - 5 * 10 ÷ 2

8 - 5 * 10 ÷ 2

Now Multiplication/Division.

This is where you must follow the order in the equation where you see the multiplication sign first, so you multiply first.

8 - 5 * 10 ÷ 2

8 - 50 ÷ 2

Next, Divide:

8 - 50 ÷ 2

8 - 25

Subtract:

8 - 25

-17

2^3 - 5 * (6 + 4) ÷ 2 = -17.

4 0
3 years ago
Read 2 more answers
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