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Dmitry [639]
3 years ago
11

A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t

he height of the big locker what is the total volume of one big locker and one small locker
Mathematics
2 answers:
I am Lyosha [343]3 years ago
7 0

Answer:

Volume of big locker = 0.36 m^{3}

Volume of small locker = 0.18 m^{3}

Total volume = 0.54 m^{3}

Step-by-step explanation:

We are given the following:

Width of larger locker = 0.5 m

Depth of larger locker = 0.6 m

Height of larger locker = 1.2 m

It is a cuboid like structure and it is well known that Volume of a cuboid structure = \text{width} \times \text{depth} \times \text{height}

So, volume of larger locker =

0.5 \times 0.6 \times 1.2\\\Rightarrow .36m^{3}

Width of smaller locker = 0.5 m

Depth of smaller locker = 0.6 m

Height of smaller locker = \dfrac{1.2}{2} = 0.6m

Volume of a cuboid structure = \text{width} \times \text{depth} \times \text{height}

So, volume of smaller locker =

0.5 \times 0.6 \times 0.6\\\Rightarrow 0.18m^{3}

Adding both the volumes, Total volume = 0.54 m^{3}

Tomtit [17]3 years ago
4 0

Answer:

0.54\,\,m^3

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × \frac{1.2}{2}=0.6\,\,m (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= 0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6

=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3

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