Answer:
I. m = 2401
II. ((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]
Step-by-step explanation:
I. Determination of m
x ∆ y = x² − 2xy + y²
2 ∆ − 5 = √m
2² − 2(2 × –5) + (–5)² = √m
4 – 2(–10) + 25 = √m
4 + 20 + 25 = √m
49 = √m
Take the square of both side
49² = m
2401 = m
m = 2401
II. Simplify ((n+1) ∆ y)/n
We'll begin by obtaining (n+1) ∆ y. This can be obtained as follow:
x ∆ y = x² − 2xy + y²
(n+1) ∆ y = (n+1)² – 2(n+1)y + y²
(n+1) ∆ y = n² + 2n + 1 – 2ny – 2y + y²
(n+1) ∆ y = n² + 2n – 2ny – 2y + y² + 1
(n+1) ∆ y = n² – 2ny + y² + 2n – 2y + 1
(n+1) ∆ y = n² – ny – ny + y² + 2n – 2y + 1
(n+1) ∆ y = n(n – y) – y(n – y) + 2(n – y) + 1
(n+1) ∆ y = (n – y + 2)(n – y) + 1
((n+1) ∆ y)/n = [(n – y + 2)(n – y) + 1] / n
((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]
Answer:
y = x + 4
Step-by-step explanation:
The equation of the line is
y = mx + c
Step 1: find the slope
m = y2 - y1 / x2 - x1
Give points
( 2 , 6) ( -2 ,2)
x1 = 2
y1 = 6
x2 = -2
y2 = 2
m = 2 - 6 / -2 - 2
m = -4 / -4
m = 1
y = mx + c
y = 1x + c
y = x + c
Step 2: sub any of the two points given into the equation
( 2 , 6)
x = 2
y = 6
y = x + c
6 = 2 + c
6 - 2 = c
c = 4
Step 3: sub c into the equation
y = x + 4
The equation of the line is
y = x + 4
Answer:
A.) Blocking occurs in an experiment when a certain experimental unit is divided or split into groups based on a certain criteria. In the experiment above, the experiment was blocked for class of runner, either professional or recreational. This is essential in other to limit the possible variability in our experiment. It is very possible thatvtve response of each class of runner may differ, therefore, it good practice to block for class of runner in other to contain the variation.
B.) Randomizing the type of shoe being worn by the runner ensures that we have given each runner an equal chance of selecting any type of shoe available,thereby eliminating biases which might emanate from fixing shoe type for each runner.
C.) Replication could simply be defined as the application of a certain treatment on more than one experimental unit. In the experiment above, by blocking for class of runner, hence having the professional and recreational units, and treatment applied to each experimental unit, Hence giving the experimenter the chance of controlling variation in the experiment.
Step-by-step explanation:
Answer:
I guess so.........................................................
Answer:
1. Perpendicular
2. Isosceles
3. Never
Step-by-step explanation:
1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.
2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )
In Δ COB , By using pythagoras : BC² = OC² + OB² ..........( 2 )
But, OA = OC because both are radius of same circle
So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC
⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.
3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius
