You can multiply everything by 7 to make things simpler.
3x + 5 = 4
3x = -1
x = -1/3
Mean weight of the bag of pears = u = 8 pounds
Standard deviation = s = 0.5 pounds
We have to find what percentage of bags of pears will weigh more than 8.25 pounds. This can be done using the z score.
We have to convert x = 8.25 to z scores, which will be:
z score = 0.5From the z table, the probability of z score being greater than 0.5 is 0.3085
Therefore, the probability of a bag to weigh more than 8.25 pounds is 0.3085
Thus 0.3085 or 31% (rounded to nearest integer) of bags of pears will have weight more than 8.25 pounds at the local market.
Answer:
D
Step-by-step explanation:
The standard deviation of the sample proportion is:

The z-score for 0.7 is:

Reference to a standard normal distribution table shows that the probability that at least 70% of the sample prefers coke to pepsi is 0.8944 or 89.44%.
Answer:
The probability that the center will have enough employees to handle this call volume is 0.2764
Step-by-step explanation:
Probability is defined as the ratio of favorable outcomes to the total number of outcomes.
Here the total mean expected number of outcomes=u = 4000
The favorable expected outcomes are = x= 22* 178= 3916
The standard deviation= σ= 5
The random variable X =178 has normal distribution with mean 4000/22 and standard deviation 5
So z= x-u/σ
Z= (3916-4000)/22/5
z= -0.764
From the table of areas under normal curve
P ( x= 3916)= P( -0.764 ≤ Z≤ 0)
P ( x= 3916)= 0.2764
The probability that the center will have enough employees to handle this call volume is 0.2764