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3 years ago

What is the gradient?

Mathematics

1 answer:

notsponge [240]3 years ago

7 0

Answer:

Gradient = 2

Step-by-step explanation:

Gradient of a line = Slope of the line

Since, slope of a line passing through two points $(x_1, y_1)$ and $(x_2,y_2)$ is given by,

Slope = $\frac{y_2-y_1}{x_2-x_1}$

Given line in the graph passes through two points (1, 0) and (2, 2)

Therefore, slope or gradient of the line = $\frac{2-0}{2-1}$

= 2

Gradient = 2 will be the answer.

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Maria makes $16 per hour. She gets a 18% raise. What is her new hourly rate?

Mariana [72]

Answer:

$18.88 per hour.

Step-by-step explanation:

We first need to find 18% of $16.

16 * 0.18 = 2.88

The pay rate increases by $2.88.

$16 + $2.88 = $18.88

Hope this helps.

8 0

2 years ago

Liam babysat for 3 1/2 hours and made $31.50. How much money does he make per hour?

anzhelika [568]

Answer:

$9 per hour

Step-by-step explanation:

31.50/3.5 = 3150/350 = 630/70 = 63/7 = 9

Hope this helps! :3

plz mark as brainliest!

5 0

3 years ago

Combine the radicals 9√x-3√x- 06 O 6√x O-6√2x 0-6

g100num [7]

Answer:

6√x

Step-by-step explanation:

9√x - 3√x = 6√x

3 0

2 years ago

A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set

lara [203]

A circle with center $(3,0)$ and radius $5$ has equation

$(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x = 16$

If we substitute $y=2x+k$ in this equation, we have

$x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0$

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

$\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0$

The expression simplifies to

$-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89$

The solutions to the associated equation are

$k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}$

So, the parabola is negative between the two solutions:

$-6-5\sqrt{5}$

8 0

3 years ago

Find the center and radius of this circle x^2+y^2-6x-10y+30=0

Vsevolod [243]

Answer:

The circle's centre is at the position (3, 5), and it has a radius of 2

Step-by-step explanation:

First let's put it in a useful format by completing the squares:

x² + y² - 6x - 10y + 30 = 0

x² - 6x + y² - 10y = -30

x² - 6x + 9 + y² - 10y + 25 = -30 + 9 + 25

(x - 3)² + (y - 5)² = 4

This tells us that the centre position is (3, 5) and the radius is √4, or 2

5 0

3 years ago