Given that oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 million barrels of oil in the well; six years later 1,500,000 barrels remain.

i.e. if V stands for volume of oil, then

$V' =kV\\dv/V= kdt\\ln V = kt+C\\V = Ae^{kt}$

To find A and k

V(0) = A = 3 million

Hence V = $3e^{kt}$

V(6) = 1.5

i.e. $1.5 = 3e^{6k}\\ln 1.5 =ln 3 +6k\\k = -0.11552$

$V(t) = 3e^{-0.11552t}$

a) Using the above value of k , we have

$V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794$ million per year.

4 0

3 years ago

Need help with this (10 points)

Nikolay [14]

Answer:

5 is greater than equal to 5. So f(5)=5+8=13

Step-by-step explanation:

7 0

2 years ago

Whats the lowest common multiple of 120 and 19600

Levart [38]

Answer:

Multiples of 120 are 120, 240, 360, 480, 600, 720, 840 etc; Multiples of 150 are 150, 300, 450, 600, 750, 900 etc; Therefore, the least common multiple of 120 and 150 is 600.

Least common multiple (LCM) of 19600 and 19619 is 384532400.

4 0

2 years ago

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