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OverLord2011 [107]
3 years ago
15

A triangular brace has an angle measure of 30 degrees, with a side opposite

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0
I think is A,,,,,,,,,,,,,,,,
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Use the given data to find the minimum sample size required to estimate a population proportion or percentage. Margin of​ error:
Yakvenalex [24]

Answer: 112

Step-by-step explanation:

Given : Significance level : \alpha=1-0.95=0.05

Critical value: z_{\alpha/2}=1.96

Margin of error : E = 9%=0.09

The estimated proportion of caret : p =0.38

Now, the formula to find the sample size :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2

i.e. n=(0.38)(1-0.38)(\dfrac{1.96}{0.09})^2

=111.738390123\approx112

Hence, the required minimum sample size = 112

6 0
3 years ago
Hi everyone! I have a very urgent work so please help me as fast as you could! I beg you. Your immediate action would be kindly
romanna [79]

Answer:

-3/8

Step-by-step explanation:

PemDas

2/3 x 3/4= 1/2

3/4 x -1/2 = -3/8

full equation is now

1/2 - 1/2 + -3/8

1/2-1/2 =0

-3/8 remains

3 0
3 years ago
Write the equation of the line that passes through the points (-3, 3) and (1, 2).
postnew [5]
Y=-1/4x+2.25

Slope: -1/4
Y-intercept: 2.25

5 0
3 years ago
Please help as soon as possible.<br> Image provided below of the answer
valentinak56 [21]
That would be first option since he did use the inverse of subtraction and added 4.5.

Insha's work is incorrectly because -4.5 + (-4.5) will not cancel each other out. It's supposed to be -9, then she should add 9 to cancel -9 out and she would have gotten 3.

Final answer: A

Hope this is clear.
3 0
4 years ago
if motorist drove a distance of 90km at constant speed for the first 40km and then drove 30 km/hr faster for the rest of the jou
elena55 [62]

Answer:

Step-by-step explanation:

The motorist drove at a distance of 90km at a constant speed for the first 40km, and then 20 km/hr faster for the rest of the journey.

The whole journey took him 1hr.

Let S denotes the average speed (in km/hr) for the first 40 km.

Hence we get the following relation,

40/S + (90 - 40)/(S + 20) = 1

or 50/(S + 20) = 1 - 40/S = (S - 40)/S

or (S + 20)(S - 40) = 50S or S^2 - 70S - 800 = 0 or (S - 80)(S + 10) = 0

or S = 80 (km/hr) [Ans]

[S cannot be negative value]

3 0
3 years ago
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