Yes,<span> is it better to have fewer clusters with more individuals when the clusters are heterogeneous?</span>
Answer:
x²
Step-by-step explanation:
The property that allow us to write
![(a+b)+c = a+(b+c)](https://tex.z-dn.net/?f=%28a%2Bb%29%2Bc%20%3D%20a%2B%28b%2Bc%29)
is called the associative property. It states exactly that, in any sum with more than two terms, you are free to substitute any pair of sum with their sum.
Answer:
is equivalent to ![m^2 \cdot n^{-2}](https://tex.z-dn.net/?f=m%5E2%20%5Ccdot%20n%5E%7B-2%7D)
Step-by-step explanation:
Using exponent rules:
![a^{-n}=\frac{1}{a^n}](https://tex.z-dn.net/?f=a%5E%7B-n%7D%3D%5Cfrac%7B1%7D%7Ba%5En%7D)
Given the expression:
![\frac{m^2}{n^2}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E2%7D%7Bn%5E2%7D)
⇒![\frac{m^2}{n^2} = m^2 \cdot \frac{1}{n^2}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5E2%7D%7Bn%5E2%7D%20%3D%20m%5E2%20%5Ccdot%20%5Cfrac%7B1%7D%7Bn%5E2%7D)
Apply the exponent rule, we have;
![m^2 \cdot n^{-2}](https://tex.z-dn.net/?f=m%5E2%20%5Ccdot%20n%5E%7B-2%7D)
Therefore, the given expression
is equivalent to ![m^2 \cdot n^{-2}](https://tex.z-dn.net/?f=m%5E2%20%5Ccdot%20n%5E%7B-2%7D)
Answer:
1/4
Step-by-step explanation:
To find the slope of a line from two points we use
m = (y2-y1)/(x2-x1)
m = (3-2)/ (3--1)
= (3-2)/(3+1)
=1/4