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Lady_Fox [76]
2 years ago
5

Let ƒ(x) = 5x − l and g(x) = x2 - 1. find (f ○ g)(−7)

Mathematics
1 answer:
attashe74 [19]2 years ago
4 0

Answer:

240

Step-by-step explanation:

5(x² - 1)

5 ((-7)² - 1)

5(49 - 1)

5 (48)

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Write the phrase as an expression. Then evaluate when y=20.
alisha [4.7K]

Answer:

Q=\frac{40}{y-16}

Q=10

Step-by-step explanation:

Let the quotient be represented by 'Q'.

Given:

The difference of a number 'y' and 16 is y-16

Quotient is the answer that we get on dividing two terms. Here, the first term is 40 and the second term is y-16. So, we divide both these terms to get an expression for 'Q'.

The quotient of 40 and y-16 is given as:

Q=\frac{40}{y-16}

Now, we need to find the quotient when y=20. Plug in 20 for 'y' in the above expression and evaluate the quotient 'Q'. This gives,

Q=\frac{40}{20-16}\\Q=\frac{40}{4}=10

Therefore, the quotient is 10, when the value of 'y' is 20.

7 0
3 years ago
What is the mixed number form<br> of 33/8
goblinko [34]
HCF of 8 that will go as much as possible to 33

4*8=32 and denominator is 8

33-32=1 which is the numerator

Answer is :

4 1/8
4 0
3 years ago
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Need help please <br> It will be good if I get the answer as soon as possible please and thanks
Ahat [919]

Answer:

B 71 & 71

Step-by-step explanation:

OP is an angle bisector

3 0
3 years ago
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Help with my homework pls<br> Solve the compound inequality y + 7 ≥ –1 and y∕4 + 3 ≤ 5.
Marianna [84]

Answer:

  -8 ≤ y ≤ 8

Step-by-step explanation:

Subtract 7 from the first one:

  y ≥ -8

Subtract 3 from the second one, then multiply by 4.

  y/4 ≤ 2

  y ≤ 8

Now, you can write these as a compound inequality:

  -8 ≤ y ≤ 8

_____

<em>Additional comment</em>

You basically solve these the same way you would an equation. The only difference is that multiplying or dividing by a negative number will reverse the inequality symbol:

  2 > 1

  -2 < -1 . . . . . multiplied above by -1.

8 0
2 years ago
Sophia has an ear infection. The doctor prescribes a course of antibiotics. Sophia is told to take 500 mg doses of the antibioti
ser-zykov [4K]

Answer:

Step-by-step explanation:

Part 1:

Let 

     Q₁ = Amount of the drug in the body after the first dose.

     Q₂ =  250 mg

As we know that after 12 hours about 4% of the drug is still present in the body.

For Q₂,

we get:

            Q₂ = 4% of Q₁ + 250

                  = (0.04 × 250) + 250

                  = 10 + 250

                  = 260 mg

Therefore, after the second dose, 260 mg of the drug is present in the body.

Now, for Q₃ :

We get;

          Q₃ = 4% of Q2 + 250

               = 0.04 × 260 + 250

               = 10.4 + 250

               = 260.4

For Q₄,

We get;

          Q₄ = 4% of Q₃ + 250 

                = 0.04 × 260.4 + 250

                = 10.416 + 250 

                = 260.416

Part 2:

To find out how large that amount is, we have to find Q₄₀.

Using the similar pattern

for Q₄₀,

We get;

           Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹

Taking 250 as common;

           Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)

                 = 2501 − 0.04401 − 0.04

           Q₄₀ = 260.4167

Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.

Part 3:

From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.

3 0
3 years ago
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