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3 years ago

PLEASE HELP QUICKLY!!!!!! ILL GIVE BRAINLIEST

Mathematics

1 answer:

Nikolay [14]3 years ago

4 0

Answer:

Step-by-step explanation:

A.) x² + 1 = 2x − 3 Make the equation into ax² + bx + c = 0. Subtract 2x on both sides, and add 3 on both sides to set the equation equal to 0

x² + 1 - 2x + 3 = 2x - 2x - 3 + 3

x² - 2x + 4 = 0

a = 1

b = -2

c = 4 This is not the answer because b = 2 not -2, and c = -4 not 4

B.) x² - 2x − 1 = 3 Subtract 3 on both sides to set the equation = 0

x² - 2x - 4 = 0

a = 1

b = -2

c = -4 This is not the answer because b = 2 not -2

C. x² + 2x - 1 = 3 Subtract 3 on both sides to set the equation = 0

x² + 2x - 4 = 0

a = 1

b = 2

c = -4 This is your answer

D. x² + 2x - 1 = -3 Add 3 on both sides to set the equation = 0

x² + 2x + 2 = 0

a = 1

b = 2

c = 2 This is not the answer because c = -4 not 2

Hope this helps :)

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Solve (3x+8)(y^2+4) dx +4

Anna35 [415]

It's been four years since I last did a problem of this particular nature. :)

Try this: divide both sides of the given equation by (x^2-5x+6), obtaining

(3x+8)(y^2+4) + 4y(x^2+5x+6) dy

-------------------- dx + ------------------------- dy = 0

x^2+5x + 6 x^2+5x + 6

This gives us:

(3x+8)(y^2+4)

-------------------- dx + 4ydy = 0

(x+2)(x+3)

Now divide all 3 terms by y^2+4:

3x+8

--------------- dx + 4ydy = 0 This completes the separation of variables.

(x+2)(x+3)

Now we'll need to integrate each of the 3 terms.

3x+8

--------------- dx + 4ydy = 0 can be re-written in the form

(x+2)(x+3)

3x +8 A B

--------------- = --------- + ---------- We will need to determine the values

(x+2)(x+3) x+2 x+3 of A and B (partial fraction expansion).

I trust you know how to do this; if not, let me know and I'll help you with that also.

I obtained B=2 and A = 1. You might want to verify that 1/(x+2) + 2/(x+3) =

3x+8

-------------- .

(x+2)(x+3)

Integrating the left side of this d. e. results in ln(x+2) + ln(x+3).

Integrating 4ydy results in 4*y^2/2, or 2y^2.

Integrating 0 results in a constant, C.

Thus,

ln(x+2) + ln(x+3) + 2y^2 = C is the solution of this d. e.

7 0

3 years ago

Consider the following trigonometric function. h(x) = 3 sin (2x - pi) + 2. Graph h(x) in the interactive widget.

Ket [755]

Answer:

Hope it helped!

Step-by-step explanation:

7 0

3 years ago

Needed quickly like asap

Artemon [7]

It is 18/20 and in simplest form it is 9/10.

Steps:
1.You have to add all the shirts, 2+7+11. This is 20, this will become your denominator

2. See what portion is NOT BLACK, the non black at 7 and 11, once you add these it becomes 18. 18 is now your numerator.

3. You now have the fraction 18/20 which you can simplify into 9/10

Hope this helps :)

4 0

3 years ago

The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot

katovenus [111]

Answer:

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

4) The data for shelter B are a symmetric data set.

True, the median is exactly 2 pounds away from each quartile which means it is symmetric.

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

Step-by-step explanation:

We are given two box-plots, a box plot basically shows 5 statistical characteristics of a data set and they are

1. minimum value

2. Lower quartile

3. Median value

4. Upper quartile

5. Maximum value

Box-plot of dogs in shelter A:

The whiskers range from 8 to 30

Which means that the range is = 30 - 8 = 22

The box ranges from 17 to 28

Which means that the interquartile range is = 28 - 17 = 11

21 - 17 = 4

28 - 21 = 9

The median is not equal distance away from each quartile which means that the box-plot is not symmetric.

A line divides the box at 21

Which means that the median is = 21

Box-plot of dogs in shelter B:

The whiskers range from 10 to 28

Which means that the range is = 28 - 10 = 20

The box ranges from 16 to 20

Which means that the interquartile range is = 20 - 16 = 4

18 - 16 = 2

20 - 18 = 2

The median is exactly 2 pounds away from each quartile which means it is symmetric.

A line divides the box at 18

Which means that the median is = 18

Which is true of the data in the box plots?

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

2) The median weight for shelter B is greater than that for shelter A.

False

3) The data for shelter A are a symmetric data set.

False

4) The data for shelter B are a symmetric data set.

True

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

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4 years ago

Solve for f(-1).<br> f(x)= -3x+3<br> f(-1)= ?

s2008m [1.1K]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers