<span>These are five questions with its five answers.
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</span><span>First, we have to explain main question.
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</span><span>The statement provides the chemical equation for the reaction of Fe with water to produce iron(III) oxide and hydrogen.
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</span><span>Fe3O4 is a weird chemical formula. It belongs to the product named oxoiron.
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Next, I have to tell how you must interpret the question. The five questions are based on the complete reaction of the same number of moles as the coefficients indicated in the chemical equation.
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<span>Those coefficients are 3 for Fe, 4 for H₂O, 1 for Fe₃O₄ and 4 for H₂.
With that understood, let's work every question.
1) How many molecules of H₂ are produced?
Answer: 4 moles of molecules.
</span><span>Justification:
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<span /><span /><span>This is, the number of moles of H₂ produced is given by the coefficient indicated in the chemical equation.
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<span>2) How many oxygen atoms are required?
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<span>Answer: 4.
</span><span>This is, the atoms of oxygen are supplied in the molecules of water. Since the coeffcient of water is 4, and each molecule o fwater has 1 atom of oxygen, 4 moles of water contain 4 moles of atoms of oxygen.
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3) How many moles of Fe₃O₄ are formed?
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<span>Answer: 1.
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<span>Justification: the coefficient of for formula Fe₃O₄ is 1, indicating that the theoretical yield is 1 mol of molecules.
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<span>4) What is the mole ratio of Fe to H₂O?
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<span>Answer: 3:4
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<span>Justification:
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</span><span>The ratio is the quotient of the two coefficients: the coefficient of the Fe divided by the coefficient of the H₂O.
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5) How many hydrogen atoms are involved in this reaction?
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<span>Answer: 8 moles of hydrogen atoms.
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<span>Justification: as you can see each molecule of H₂O has 2 atoms of hydrogen, then 4 moles of molecules of H₂O have 8 moles of atoms of hydrogen. And of course the same number are in the produt: 4 moles of H₂ contain 8 moles of atomos of hydrogen
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The mass isnt relevant
520 - 120 = 400
400 / 8 = 50
50ms^-2
solution:
the given compounds are sodium acetate, 1M HCL,NaHCO₃ and Na2CO₃
pH of the buffer solution is 4.7
the value of pKa of sodium bicarbonate is 6.37
the value of pKa of acetic acid is 4.7
calculate concentration of acetic acid by using the following forumula
pH=pKa+lag[salt]/[acid]
substitute the pH and Pka values in the formula.
4.7=4.7+log[salt]/[acid]
log[salt]/[acid]=0
thus, the concentration ratio of the salt and acid should be equal to each other.
Thus, concentration of sodium acetate is 0.05M
Concentration of sodium acetate= concentration of acid
= 0.05M
Volume of the buffer solution is 100mL
The buffer solution can be prepared as 0.05M of 50mL sodium acetate will react with 0.05M of 50mL of 0.05M of HCL.
The chemical equation for neutralization of the weak base with strong can be represented as show as
CH₃COONa+HCL-->CH₃COOH+NaCL
