1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Varvara68 [4.7K]
3 years ago
7

2. What is an example of a molecule with different types of atoms?

Chemistry
1 answer:
agasfer [191]3 years ago
4 0

Answer:

a compound

Explanation:

A molecule with multiple atoms is compound like water it's made up of 1 oxygen and two hydrogen.

You might be interested in
As the temperature of a gas in a closed container increases, what is true of the particles in the substance? (2 points)
Misha Larkins [42]
The rate of movement increases, as they get faster with more energy.
8 0
3 years ago
Read 2 more answers
A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i
Alexeev081 [22]

Answer:

MM_{acid}=140.1g/mol

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}

Thus, solving for the moles of the acid, we obtain:

n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol

Then, by using the mass of the acid, we compute its molar mass:

MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol

Regards.

7 0
3 years ago
In a chemical reaction,_______________are the substances present after the reaction.
dsp73

Answer:

In a chemical reaction, <u>products</u> are the substances present after the reaction

8 0
3 years ago
Read 2 more answers
Calculate the molality of a 20.0% by mass ammonium sulfate (nh4)2so4 solution. the density of the solution is 1.117 g/ml.
olasank [31]
Hello!

We have the following data:

m1 (solute mass) = 20 % m/m
M1 (Molar mass of solute) (NH4)2 SO4 = ?
m2 (mass of the solvent) = ? (in Kg)

First we find the solute mass (m1), knowing that:

20% m/m = 20g/100mL

20 ------ 100 mL (0,1 L)
y g --------------- 1 L

y = 20/0,1 
y = 200 g --> m1 = 200 g

Let's find Solute's Molar Mass, let's see:

M1 of (Nh4)2SO4
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol

We must find the volume of the solvent and therefore its mass (m2), let us see:

d = 1,117 g/mL
m = 200 g
v (volumen of solute) = ?

d =  \dfrac{m}{V} \to V =  \dfrac{m}{d}

V =  \dfrac{200\:\diagup\!\!\!\!g}{1,117\:\diagup\!\!\!\!g/mL} \to V = 179\:mL\:(volumen\:of\:solute)

<span>The solvent volume will be:
</span>
1000 -179 => V = 821 mL (volumen of disolvent)

If: 1 mL = 1g

<span>Then the mass of the solvent is:
</span>
m2 (mass of the solvent) = 821 g → m2 (mass of the solvent) = 0,821 Kg

Now, we apply all the data found to the formula of Molality, let us see:

\omega =  \dfrac{m_1}{M_1*m_2}

\omega =  \dfrac{200}{132*0,821}

\omega =  \dfrac{200}{108,372}

\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark

_________________________________
_________________________________


<span>Another way to find the answer:
</span>
We have the following data: 

W (molality) = ? (in molal)
n (number of mols) = ?
m1 (solute mass) = 20 % m/m = 20g/100mL → (in g to 1L) = 200 g
m2 (disolvent mass) the remaining percentage, in the case: 80 % m/m = 800 g → m2 (disolvent mass) = 0,8 Kg
M1 (Molar mass of solute) (NH4)2 SO4 
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol 


<span>Let's find the number of mols (n), let's see:

</span>n =  \dfrac{m_1}{M_1}

n = \dfrac{200}{132}

n \approx 1,5\:mol

Now, we apply all the data found to the formula of Molality, let us see:

\omega =  \dfrac{n}{m_2}

\omega =  \dfrac{1,5}{0,8}

&#10;\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark

I hope this helps. =)
7 0
3 years ago
Amanda wants to paint the ceiling of her restaurant. The ceiling is in the shape of a square. Its side lengths are 39 feet. Supp
Delvig [45]

if da ceiling in a square that means it has four sides. If each side is 39 feet and there are four sides you would multiply 39 times 4 which equals 156. If one can of paint can cover 169 ft.² and the ceiling is only 156 ft.² then you would only need 1 CAN OF PAINT.

7 0
3 years ago
Other questions:
  • What type of energy cause salt to separate from water​
    11·1 answer
  • Active and inactive volcano in philipines?
    14·1 answer
  • A sample of nitrogen gas occupies 1.55 L at
    9·1 answer
  • If answered correctly i will give brainlest​
    14·2 answers
  • Which of the following is an example of erosion?
    7·2 answers
  • PLEASE HELP !<br><br> Convert 0.429 mol AlCl3 to grams
    7·1 answer
  • To make an object start moving, you must exert a force in
    7·1 answer
  • What are the rows of the periodic table called?
    12·1 answer
  • Neutrons have neither charge nor mass.<br> TRUE<br> FALSE
    10·1 answer
  • A chemist prepares a solution of copper) sulfate (cuso4)by weighing out 29.9 g of copper ) sulfate into a 150 into a 150.mLvolum
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!