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3 years ago

2. What is an example of a molecule with different types of atoms?

Chemistry

1 answer:

agasfer [191]3 years ago

4 0

Answer:

a compound

Explanation:

A molecule with multiple atoms is compound like water it's made up of 1 oxygen and two hydrogen.

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HELP ITS DUE TOMORROW

tangare [24]

Answer:

like i said put them all in numeral order and youll get them right

Explanation:

4 0

2 years ago

Read 2 more answers

What is the percent-by-mass, %(m/m), concentration of sucrose ( table sugar) in a solution made by dissolving 22.8 g of sucrose

Ede4ka [16]

Answer:

32.6 %

Explanation:

Given data

Mass of sucrose (solute): 22.8 grams

Mass of water (solvent): 47.1 grams

Step 1: Calculate the mass of the solution

The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.

m(solution) = m(solute) + m(solvent)

m(solution) = 22.8 g + 47.1 g

m(solution) = 69.9 g

Step 2: Calculate the percent-by-mass of sucrose in the solution

We will use the following expression.

$\% m/m = \frac{mass\ of\ sucrose}{mass\ of\ solution} \times 100\% = \frac{22.8g}{69.9g} \times 100\% = 32.6 \%$

5 0

2 years ago

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Find the boiling point temperature at 760 torr of an isomer of octane, c8h18, if its enthalpy of vaporization is 38,210 j mol-1

mixas84 [53]

According to Clausius-Clayperon equation,

$ln(\frac{P_{1} }{P_{2} }) = \frac{delta H_{vap} }{R} (\frac{1}{T_{2} }-\frac{1}{T_{1} } )$

$P_{1}$ is the vapor pressure at boiling point = 760 torr

$P_{2}$ is the vapor pressure at T_{2} =638.43 torr

Temperature $T_{2} = 110.0^{0}C + 273 = 383 K$

Δ $H_{vap} = 38210 J/mol$

Plugging in the values, we get

$ln(\frac{P_{1} }{P_{2} }) = \frac{delta H_{vap} }{R} (\frac{1}{T_{2} }-\frac{1}{T_{1} } )$

ln $\frac{760 torr}{638.43 torr} =\frac{38210 J/mol}{8.314 J/(mol.K)} (\frac{1}{383 K}-\frac{1}{T_{1} }$

$T_{1} = 389 K$

Therefore, the boiling point of octane = 389 K - 273 = $116^{0}C$

7 0

2 years ago

An unknown insoluble substance displaced the water shown. It's mass is indicated on the triple beam balance. Mass = A. 694 B. 69

vodka [1.7K]

Answer:

D. 693.8.

Explanation:

The first scale of the triple beam balance indicate that the mass is 600.

The second scale of the triple beam balance indicate that the mass is 690.

The third scale of the triple beam balance indicate that the mass is higher that 693.5 and the scale is near but lower than 694, so the mass = 693.8.c

3 0

3 years ago

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How many molecules of water are there in 0.234 L of water

tankabanditka [31]

Answer:

7.82x10^24 molecules of water

Explanation:

H2O=18.015 g/mol Avogadro's #=6.022x10^23 molecules

0.234L x 1000g/1L x 1 mol H2O/18.015 g x 6.022x10^23 = 7.82x10^23 molecules of water

3 0

2 years ago