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alekssr [168]
3 years ago
15

For elements (Br, Ca, Fe, Na, S, Si, and Xe) which of the following term(s) apply?

Chemistry
1 answer:
ioda3 years ago
3 0

Answer:

Detail is given below.

Explanation:

Bromine: Br (Halogen and non metal)

Bromine is present in group 17 and it is called halogen.

All halogens are very reactive.

Calcium; Ca ( alkaline earth metal)

Calcium is present in group 2. It is alkaline earth metal.

It has two valance electrons.

Iron; Fe (Transition metal)

Iron is transition metal and also called d-block element.

Sodium: Na (Metal, main group element)

Sodium is metal and present in group one.

It has one valance electron.

Sulfur: S (non metal)

Sulfur is non metal. It is present in group 16.

It has six valance electrons.

Silicon: Si (metalloid)

Silicon is metalloid. It is present in group 14.

It has four valance electrons.

Xenon: Xe (Noble gas, gas at a room temperature)

it is noble gas. Xenon is present in group 18.

It is gas at a room temperature.

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An iron ore sample weighing 0.5562 g is dissolved HCl (aq), and the iron is obtained as Fe2 in solution. This solution is then t
erik [133]

Answer:

\% Fe^{+2}=70%

Explanation:

Hello,

In this case, we could considering this as a redox titration:

Fe^{+2}+(Cr_2O_7)^{-2}\rightarrow Fe^{+3}+Cr^{+3}

Thus, the balance turns out (by adding both hydrogen ions and water):

Fe^{+2}\rightarrow Fe^{+3}+1e^-\\(Cr_2^{+6}O_7)^{-2}+14H^++6e^-\rightarrow 2Cr^{+3}+7H_2O\\\\6Fe^{+2}+(Cr_2^{+6}O_7)^{-2}+14H^++6e^-\rightarrow Cr^{+3}+7H_2O+6Fe^{+3}+6e^-

Thus, by stoichiometry, the grams of Fe+2 ions result:

m_{Fe^{+2}}=0.04021\frac{molK_2Cr_2O_7}{L}*0.02872L*\frac{6molFe^{+2}}{1molK_2Cr_2O_7}*\frac{56gFe^{+2}}{1molFe^{+2}}=0.388gFe^{+2}

Finally, the mass percent is:

\% Fe^{+2}=\frac{0.388g}{0.5562g}*100\%\\  \% Fe^{+2}=70%

Best regards.

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