They attract because they have opposite charges
Answer:
The no. of protons = atomic number
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Answer:
ΔH
°fCaO= -655.09 KJ/mol = ΔH
°fCaO
Explanation:
ΔH
°(reaction)a=ΔH
°f(product)-ΔH
°f(reactant)
where,
ΔH
°f(product)=is the standard heat of formation of products
-ΔH
°f(reactant)=is the standard heat of formation of reactants
The standard heat of formation of H
2
O
(
l
) is −
285.8
k
J
/
m
o
l
.
The standard heat of formation of Ca(OH
)2 is −
986.09
k
J
/
m
o
l
.
For the given reaction, the standard enthalpy change is calculated by the expression shown below.
ΔH
°(reaction)a=ΔH
°f(CaO+H2O)-ΔH
°f(Ca(OH)₂
65.2 = ΔH
°fCaO+( -265.8) -(-986.09)
= ΔH
°fCaO-265.8+986.09
65.2 = ΔH
°fCaO+ 720.29
65.2-720.29 = ΔH
°fCaO
-655.09 KJ/mol == ΔH
°fCaO
In NH4OH, the compounds that make it up are NH4+ and OH-
Therefore N exists in the ammonium form.
In the ammonium ion 4H atoms are connected to N.
N is more electronegative than H, therefore when H bonds to N, H is the more positive atom therefore each H has a charge of +1, since there are 4 H atoms the charge contributed by the 4H atoms are +1 * 4 = +4
the overall charge of NH4 is +1
Charge of N (+) +4 = +1
Charge of N = +1 - 4
Therefore oxidation state of N in NH4 is = -3
They are called equivalent sets
