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Lemur [1.5K]
3 years ago
5

A 12.2-g sample of X reacts with a sample of Y to form 78.9g of XY. what mass of Y reacted?​

Chemistry
1 answer:
barxatty [35]3 years ago
3 0

Answer:

The answer to your question is:  y = 66.7g

Explanation:

To solve this problem we must remember the Lavoisier law of conservation of mass, that stated that the mass can not be created or destroyed but it changes forms.

So, the mass of the reactants is equal to the mass of the products.

Process

                x          +          y             ⇒           xy

             12.2g                   ?                         78.9 g

           12.2 g + y = 78.9g

           y = 78.9 - 12.2

           y = 66.7g

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3 years ago
WILL GIVE BRAINLIEST
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Answer:

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Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C.

In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C.

What if you wanted to increase the temperature of 1 g of water by 2∘C ?

This will account for increasing the temperature of the first gram of the sample by n∘C, of the the second gramby n∘C, of the third gram by n∘C, and so on until you reach m grams of water.

And there you have it. The equation that describes all this will thus be

q=m⋅c⋅ΔT , where

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m - the mass of the sample

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4 0
3 years ago
For the decomposition of calcium carbonate, consider the following thermodynamic data (Due to variations in thermodynamic values
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Answer : The temperature in kelvins is, T>1108.695K

Explanation : Given,

\Delta H = 178.5 KJ/mole = 178500 J/mole

\Delta S = 161.0 J/mole.K

Gibbs–Helmholtz equation is :

\Delta G=\Delta H-T\Delta S

As per question the reaction is spontaneous that means the value of \Delta G is negative or we can say that the value of \Delta G is less than zero.

\Delta

The above expression will be:

0>\Delta H-T\Delta S

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T>\frac{\Delta H}{\Delta S}

Now put all the given values in this expression, we get :

T>\frac{178500J/mole}{161.0J/mole.K}

T>1108.695K

Therefore, the temperature in kelvins is, T>1108.695K

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