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Sphinxa [80]
3 years ago
14

A) how many hydrogen atoms are in an acyclic alkane with 5 carbon atoms?

Chemistry
1 answer:
sattari [20]3 years ago
4 0
Acyclic alkanes can be straight chain or branch.so if we utilise the general formula for alkanes(excluding cycloalkanes) CnH(2n+2) we can get the number of hydrogen atoms for a 5carbon atom acyclic all and to be 2(5)+2=12
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Fill in the coefficients that was will balance the following reaction SnSO4 + KBr SnBr2 K2SO4
Juliette [100K]

The coefficients are 1 : 2 : 1 : 1

<u>Explanation:</u>

To be a balanced equation, the chemical equation should have has equal number of atoms on both reactant and product side.

Given chemical equation:

        a_{0} {SnSO}_{4}+a_{1} K B r \rightarrow a_{2} {SnBr}_{2}+a_{3} K_{2} S O_{4}

Now, calculate the number of atoms present in reactant side:

Sn - 1

S O_{4} - 1

K - 1

Br - 1

Then, calculate the number of atoms present in product side:

Sn - 1

S O_{4} - 1

K - 2

Br - 2

Therefore, in order to balance this given chemical equation multiply KBr by 2 on reactant side. So, the balanced chemical equation is as follows.

       \Sn S O_{4}+2 K B r \rightarrow S n B r_{2}+K_{2} S O_{4}

Hence,

a_{0} - 1\\a_{1} - 2\\a_{2} - 1\\a_{3} - 1

8 0
3 years ago
Would chromium-51 be useful for dating rocks containing chromium?
Over [174]
The half-life of chromium-51 is a very short period of time so no because it would be so little left that it would be difficult to detect.
Hope this helps!!
8 0
2 years ago
Compare the occurrence of heavier elements on earth and the universe.
k0ka [10]
By definition, a heavy element is a specific kind of element with a larger atomic mass. An element could be considered as "heavy" if its atomic number is greater already than 92. One of the known heavy elements on Earth is Tennessine and Tungsten while in the universe are lithium-5 and berryllium-8.
3 0
3 years ago
NASA's Parker Solar Probe is currently en route to the outer corona of the sun. At its closest approach it will be traveling at
Digiron [165]

Answer:

120.822\frac{mi}{s} will be the speed in \frac{mi}{s}

Explanation:

This is a unit conversion problem.

To solve it, we need the equivalences between km and ft, ft and mi and hr and s.

The equivalences are :

5280 ft=1 mi\\1km=3280.84 ft\\1hr=60 min\\1min=60s

If 5280ft=1mi then

\frac{5280ft}{1mi}=1\\\frac{1mi}{5280ft}=1

The trick is to multiply by one the speed given until to convert it in mi/s units

(7.00).10^{5}\frac{km}{hr}.\frac{3280.84ft}{1km}.\frac{1mi}{5280ft}.\frac{1hr}{60min}.\frac{1min}{60s}=120.822\frac{mi}{s}

Notice that km,ft,hr and min have been cancelled.

Be careful of the fraction order.

Multiply by ft/km is different that multiply by km/ft

6 0
3 years ago
At STP, which gas sample has the same number of molecules as 2.0 liters of CH4(g) at STP?
Elza [17]

Answer:

the same number of molecule 2.0 liters of o2(g) at STP

6 0
3 years ago
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