A) how many hydrogen atoms are in an acyclic alkane with 5 carbon atoms?

1 answer:

4 0

Acyclic alkanes can be straight chain or branch.so if we utilise the general formula for alkanes(excluding cycloalkanes) CnH(2n+2) we can get the number of hydrogen atoms for a 5carbon atom acyclic all and to be 2(5)+2=12

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Fill in the coefficients that was will balance the following reaction SnSO4 + KBr SnBr2 K2SO4

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<u>Explanation:</u>

To be a balanced equation, the chemical equation should have has equal number of atoms on both reactant and product side.

Given chemical equation:

$a_{0} {SnSO}_{4}+a_{1} K B r \rightarrow a_{2} {SnBr}_{2}+a_{3} K_{2} S O_{4}$

Now, calculate the number of atoms present in reactant side:

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Then, calculate the number of atoms present in product side:

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Therefore, in order to balance this given chemical equation multiply KBr by 2 on reactant side. So, the balanced chemical equation is as follows.

$\Sn S O_{4}+2 K B r \rightarrow S n B r_{2}+K_{2} S O_{4}$

Hence,

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