Answer:
6 carbon dioxide molecules
Explanation:
The Calvin cycle generates the necessary reactions for the fixation of carbon in a solid structure for the formation of glucose and, in turn, regenerates the molecules for the continuation of the cycle.
The Calvin cycle is also known as the dark phase of photosynthesis or also called the carbon fixation phase. It is known as the dark phase because it is not light dependent as is the first phase or light phase
.
This second stage of photosynthesis fixes the carbon of the absorbed carbon dioxide and generates the precise number of biochemical elements and processes necessary to produce sugar and recycle the remaining material for continuous production.
The Calvin cycle uses the energy produced in the light phase of photosynthesis to fix the carbon dioxide (CO2) carbon in a solid structure such as glucose, in order to generate energy.
The glucose molecule composed of a six-carbon main structure will be further processed in glycolysis for the preparatory phase of the Krebs cycle, both part of the cellular respiration.
The Calvin cycle produces in six turns a six-carbon glucose molecule and regenerates three RuBP that will be catalyzed again by the RuBisCo enzyme with CO2 molecules for the restart of the Calvin cycle.
The Calvin cycle requires six molecules of CO2, 18 ATP and 12 NADPH produced in the light phase of photosynthesis to produce a glucose molecule and regenerate three RuBP molecules.
Explanation:
1. K (Potassium)
2. Te (Tellurium)
3. F (Flourine)
4. group 11, period 4
5. group 18, period 4
6. group 12, period 6
7. Cl
8. Pb
9. W
10. Sb
11. Na
12. period 6, group 11
13. period 5, group 11
14. period 2, group 16
15. Groups 13–16 of the periodic table contain one or more metalloids
16. Hydrogen
17. Helium
18. Calcium
19. Cobalt
20. Carbon
Answer:
0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂
Explanation:
In first place, the balanced reaction between Mg and O₂ is:
2 Mg + O₂ ⇒ 2 MgO
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactants and products participate in the reaction:
- Mg: 2 moles
- O₂: 1 mole
- MgO: 2 moles
Then you can apply the following rule of three: if by reaction stoichiometry 2 moles of Mg produce 2 moles of MgO, 0.250 moles of Mg, how many moles of MgO will they form?
moles of MgO= 0.250
<u><em>0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂</em></u>
Answer:
When electrons flow through a conductor such as a wire, it is called, "Electricity".
Explanation:
Answer:
Explanation:
This is a limiting reactant problem.
Mg(s)
+
2HCl(aq)
→
MgCl
2
(
aq
)
+ H
2
(
g
)
Determine Moles of Magnesium
Divide the given mass of magnesium by its molar mass (atomic weight on periodic table in g/mol).
4.86
g Mg
×
1
mol Mg
24.3050
g Mg
=
0.200 mol Mg
Determine Moles of 2M Hydrochloric Acid
Convert
100 cm
3
to
100 mL
and then to
0.1 L
.
1 dm
3
=
1 L
Convert
2.00 mol/dm
3
to
2.00 mol/L
Multiply
0.1
L
times
2.00 mol/L
.
100
cm
3
×
1
mL
1
cm
3
×
1
L
1000
mL
=
0.1 L HCl
2.00 mol/dm
3
=
2.00 mol/L
0.1
L
×
2.00
mol
1
L
=
0.200 mol HCl
Multiply the moles of each reactant times the appropriate mole ratio from the balanced equation. Then multiply times the molar mass of hydrogen gas,
2.01588 g/mol
0.200
mol Mg
×
1
mol H
2
1
mol Mg
×
2.01588
g H
2
1
mol H
2
=
0.403 g H
2
0.200
mol HCl
×
1
mol H
2
2
mol HCl
×
2.01588
g H
2
1
mol H
2
=
0.202 g H
2
The limiting reactant is
HCl
, which will produce
0.202 g H
2
under the stated conditions.
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