All categories

3 years ago

Metals experience plastic deformation when _____. A. Their crystal patterns have been disrupted by stress

Chemistry

1 answer:

zaharov [31]3 years ago

5 0

Answer: Option (A) is the correct answer.

Explanation:

Plastic deformation is the change in shape of an object or metal caused by the load of excess stress.

Thus, metals experience plastic deformation when their crystal patterns have been disrupted by stress.

When stress is provided to the metal then their crystal pattern gets deformed resulting in change of shape of the metal. Plastic deformation is a permanent deformation.

You might be interested in

(20 Points)

kogti [31]

A. It is Basic

for example,

NaOH → Na⁺(aq) + OH⁻(aq)
Ba(OH)₂ → Ba²⁺(aq) + 2OH⁻(aq)
Ca(OH)₂ → Ca²⁺(aq) + 2OH⁻(aq)

pH>7

6 0

2 years ago

Read 2 more answers

If you have an altitude of 55 mi. (miles), which layer of the atmosphere are you in?

Kruka [31]

$Answer:$ $You$ $would$ $be$ $in$ $the$ $D-region$

$The$ $reason$ $I$ $understand$ $this$ $is$ $because$ $the$ $D-region$ $stands$ $55$ $miles$ $in$ $altitude$ , $despite$ $it$ $will$ $likely$ $vanishes$ $at$ $night$ .

8 0

2 years ago

A 45.0-gram sample of copper metal was heated from 20.0°C to 100.0°C. Calculate the heat absorbed, in kJ, by the metal.

s2008m [1.1K]

Answer:

1.386 KJ

Explanation:

From the question given above, the following data were obtained:

Mass (M) of copper = 45 g

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T1) = 20.0°C

Final temperature (T2) = 100.0°C

Change in temperature (ΔT) =?

ΔT = T2 – T1

ΔT = 100 – 20

ΔT = 80 °C

Next, we shall determine the heat absorbed by the sample of copper as follow:

Mass (M) of copper = 45 g

Change in temperature (ΔT) = 80 °C

Specific heat capacity (C) of copper = 0.385 J/gºC

Heat absorbed (Q) =..?

Q = MCΔT

Q = 45 × 0.385 × 80

Q = 1386 J

Finally, we shall convert 1386 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

1386 J = 1386 J × 1 KJ /1000 J

1386 J = 1.386 KJ

Thus, the heat absorbed by the sample of the sample of copper is 1.386 KJ.

5 0

2 years ago

A 0.500-g sample of KCl is added to 50.0g of water in a calprimeter (Figure 5.12) If the temperature decreases by 1.05C. what is

Sauron [17]

Answer : The reaction is endothermic.

Explanation :

Formula used :

$Q=m\times c\times \Delta T$

where,

$\Delta T$ = change in temperature = $1.05^oC$

Q = heat involved in the dissolution of KCl = ?

m = mass = 0.500 + 50.0 = 50.5 g

c = specific heat of resulting solution = $4.18J/g^oC$

Now put all the given value in the above formula, we get:

$Q=50.5g\times 4.18J/g^oC\times 1.05^oC$

$Q=+221.64J$

The heat involved in the dissolution of KCl is positive that means as the change in temperature decreases then the reaction is endothermic and as the change in temperature increases then the reaction is exothermic.

Hence, the reaction is endothermic.

8 0

3 years ago

URGENT

Vadim26 [7]

Answer:

Explanation:

Discussion

When Pressure increases equilibrium shifts to the side with the smallest number of moles. But which side is that?

N2(g) + 3H2(g) ⇌ 2NH3(g)

The left side has 1 mol of nitrogen (N2) and 3 moles of Hydrogen = 4 mols

on the left side.

The right side has 2 mols of NH3 = 2 mols on the right.

Conclusion: You tell the number of mols by the Balance numbers to the left of each chemical in an equation.

Since the left side N2 + 3H2 = 4 mols, the equilibrium does NOT shift left.

2NH3 is only two mols.

The equilibrium shifts Right

Answer

7 0

2 years ago