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3 years ago

The polynomial 8x2 – 8x + 2 – 5 + x is simplified to 8x2 – gx – h. What are the value of g and h?

Mathematics

1 answer:

docker41 [41]3 years ago

3 0

Answer:

Step-by-step explanation:

8x^2 - 8x + 2 - 5 + x.....combine like terms

8x^2 - 7x - 3 <=== g = 7 and h = 3

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you have a work meeting that starts at 1:15 pm. you arrived at 12:53 pm. how many minutes early were you?

Inessa05 [86]

I totally forgot that I am having meeting at my work place. All of sudden, I remembered that meeting through a hint given by my colleague while having discussion about our project work. I have to present a topic which I didn't prepare yet. Meeting is at 1.15pm. OMG! It's already 12.30 pm. Within few minutes I went to the meeting place with my topic. When I entered the meeting hall, the time was 12.53pm. I was happy to know that I arrived 22 minutes earlier.

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3 years ago

How many terms in 2-8+22<br> A. 1<br> B. 2<br> C. 3<br> D. 26

natima [27]

Answer:

6 is the answer.

is it right

4 0

3 years ago

Usethe distributive property to express28+42

tankabanditka [31]

Answer:

To express the sum of two numbers using distributive property, we factor out the highest common factor (HCF) of the two numbers (i.e. the greatest number that can divide the two numbers without remainder)

28 = 2 x 2 x 7

42 = 2 x 3 x 7

The HCF of 28 and 42 is given by 2 x 7 = 14

Therefore, we express 28 + 42 using distributive property thus: 14(2 + 3)

4 0

3 years ago

Read 2 more answers

NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

2 years ago

For Exercises 19-24, a, b, c, and d are distinct lines in the same plane. For each combination of relationships, tell how a and

Olegator [25]

Answer:

a is parallel to d

a and d are parallel, and are perpendicular to c and d (those are parallel to each other)

RESULT

They are parallel

Step-by-step explanation:

5 0

2 years ago