Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
what grade really quick
Step-by-step explanation:
Answer:
Step-by-step explanation:
we have
Solve for h
That means ----> isolate the variable h
step 1
Multiply by 6 both sides
step 2
Divide by 
both sides
Answer:
-1/2
Step-by-step explanation:
it has to be a negative number since
every other number is negative
its a fraction since the numbers are decreasing
96 divided by 48 is 2
so the number being multiplied or ration must be -1/2
Steps to solve:
5x² = 15x
~Subtract 15x to both sides
5x² - 15x = 15x - 15x
~Simplify
5x² - 15x = 0
~Factor left side
5x(x - 3) = 0
~Factors equal 0
5x = 0 and x - 3 = 0
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~Simplify 5x = 0
5x/5 = 0/5
x = 0
~Simplify x - 3 = 0
x - 3 + 3 = 0 + 3
x = 3
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Thus, the correct answer is 0, 3.
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Best of Luck!
