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EastWind [94]
4 years ago
7

How many water molecules are in a block of ice containing 1.75 mol of water (H2O)?

Chemistry
2 answers:
AnnyKZ [126]4 years ago
5 0
1.75 mol H2O x (6.022x10^23 molecules H2O / 1 mol H2O) = 1.05x10^24 molecules H2O
dusya [7]4 years ago
3 0
(6.02*10^23)=1.0535*10^24
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if you find that a substance turns litmus paper to blue and contains hydroxide ions, it is most likely
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4 years ago
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What is the volume of a balloon containing 0.75 moles of gas at STP?
disa [49]

Answer:

V = 16.81 L

Explanation:

Given data:

Number of moles = 0.75 mol

Temperature = standard = 273 K

Pressure = 1 atm

Volume of balloon = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

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V = volume

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T = temperature in kelvin

Now we will rearrange the formula.

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6 0
3 years ago
What are some chemical changes that occur at school at home and in nature
Travka [436]

Chemical changes are irreversible.

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6 0
4 years ago
What is the freezing point of a solution that contains 12.0 g of glucose (C6H12O6) in 50 g of acetic acid (CH3COOH). For acetic
sergij07 [2.7K]

Answer:

T = 11.4°C

Explanation:

Given that:

weight of solute  w (glucose) = 12 g

weight of solvent W (acetic acid) = 50 g

Molar depression constant of solvent (Kf)= 3.90°C/m

Temperature of solvent freezing point T₀ = 16.6°C

Temperature of solution freezing point Tₓ = (T₀ -T) = ???

Molar mass of solute (glucose) = 180.2 g/mol

Using the expression;

(T₀ -T) = \frac{1000*k_f*w}{MM*W}

(16.6-T)=\frac{1000*3.90*12}{180.2*50}

(16.6-T)=\frac{46800}{9010}

(16.6-T) = 5.194^0C

(16.6-T) = 5.2^0C

-T = -16.6 °C + 5.2 °C

- T = -11.4°C

T = 11.4°C

∴ The freezing point of the solution is said to be = 11.4°C

6 0
4 years ago
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