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2 years ago

I need help ASAP please I'm gonna fail

Mathematics

1 answer:

lianna [129]2 years ago

5 0

Answer:

Class 1 only

Step-by-step explanation:

I could explain but it sounds like you need an answer quick...

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100% =3200<br>70% = ????

SVEN [57.7K]

Answer:

2240

Step-by-step explanation:

plz fo"ow ms

mark me as brainlist

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2 years ago

Read 2 more answers

The population of Metsville is 1,274 people less than the population of Eden. If the population of Eden is 9,021 people, what is

yawa3891 [41]

Answer:

7,747

Step-by-step explanation:

9,021-1,274=7,747

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2 years ago

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Safety regulations require that the time between airplane takeoffs (on the same runway) will be at least 3 minutes. When taking

Alenkinab [10]

Answer:

1.96 planes

Step-by-step explanation:

The computation of the number of planes is shown below:

As we know that

System Inventory is

= Flow rate in the system × Throughput time

where,

Flow rate is

= Frequency of taken off

= 16 planes ÷ hour

= 16 ÷ 60 Planes per minute

Throughput time is

= runway waiting time + runway Run time

= 33 seconds + 6 minutes × 60 seconds + 48 seconds

= 441 seconds

= 441 per 60 seconds

Therefore the number of planes is

$= \frac{441}{60} \times \frac{16}{60}$

= 1.96 planes

4 0

2 years ago

The local bike shop sells a bike and accessories package for $266. If the bike is worth 6 times more than the accessories, how m

tatiyna

Do 6x 266 in your calculator that’s ur answer

7 0

2 years ago

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

2 years ago