Question

In ΔCDE, the measure of ∠E=90°, the measure of ∠C=70°, and DE = 12 feet. Find the length of CD to the nearest tenth of a foot

Answer 1

Answer:

$CD = 4.4ft$

Step-by-step explanation:

Given

$DE = 12$

$\angle C = 70^\circ$

Required

Find CD

This question is represented with the attached triangle

To solve CD, we make use of tan formula.

$tan(70) = \frac{DE}{CD}$

Substitute 12 for DE

$tan(70) = \frac{12}{CD}$

Make CD the subject

$CD = \frac{12}{tan(70)}$

$CD = \frac{12}{2.7475}$

$CD = 4.4ft$ --- approximated

Answer 2

Answer:

12.8

Step-by-step explanation: