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3 years ago

The length of the road is 1000 miles. If 1 inch represents 100 miles, what is the length of the road on the map?

Mathematics

2 answers:

-BARSIC- [3]3 years ago

6 0

Answer:

10 Inches.

Step-by-step explanation:

1000 divided by 100 = 10.

Ket [755]3 years ago

6 0

Answer:

10 inches

Step-by-step explanation

So if 1 inch represents 100 miles than if u divide 1000 by 100=10 so it would be 10 inches

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Plz answer. only if correct

earnstyle [38]

Answer:10001.5%+10303990=f(g+2)

Step-by-step explanation:

i dont remeber how to do this cap

5 0

3 years ago

5.7 x 0.049 ÷ 0.681

Novay_Z [31]

Use a calculator!!!!

4 0

3 years ago

Read 2 more answers

Allen is horrible at managing his money. For example, he

N76 [4]

Answer:

$80,000

Step-by-step explanation:

Define the variables:

Let x = "fish-flavored" chicken company investment (in dollars)

Let y = spray-on vitamins company investment (in dollars)

If Allen invested a total of $100,000:

⇒ x + y = 100000

Given:

3% profit on "fish-flavored" chicken investment
1% profit on pray-on vitamins investment
Total profit = $2,600

⇒ 0.03x + 0.01y = 2600

Rewrite the first equation to make y the subject:

⇒ y = 100000 - x

Substitute into the second equation and solve for x:

⇒ 0.03x + 0.01(100000 - x) = 2600

⇒ 0.03x + 1000 - 0.01x = 2600

⇒ 0.02x + 1000 = 2600

⇒ 0.02x = 1600

⇒ x = 80000

Therefore, Allen invested $80,000 in the "fish-flavored" chicken company.

6 0

2 years ago

Need answer ASAP Express a 10/3 b 7/3 in simplified radical form.

anastassius [24]

I guess this is what you mean 3√a^10 and 3√b^7

5 0

3 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

3 years ago