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3 years ago

4. What is the unit price if 5 pounds of fruit cost $8.40?

1 answer:

3 0

8.40$ divided by 5 = 1.68$ each pound which makes 1.68$ the unit price per pound.

Now to check the answer 1.68$ times 5 gives us a total of 8.40$

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Helpp!!!

astraxan [27]

9514 1404 393

Answer:

11.9 cm

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation between the side opposite the angle (BC) and the hypotenuse (14 cm).

Sin = Opposite/Hypotenuse

sin(58°) = BC/(14 cm)

BC = (14 cm)×sin(58°) . . . . . multiply by the denominator

BC ≈ 11.9 cm

5 0

3 years ago

HELP ME please this is due tomorrow

bonufazy [111]

Answer:(12 cm) x (7 cm) x (6 cm) x 8.4 =

4.2336 liters

4 0

2 years ago

The diameter of a dime is seven hundred five thousandths of an inch

muminat

7.9 millimeters (0.705 inch) in diameter. So yes it is.

6 0

3 years ago

In 2016, a town had a population of 80,000 people. The growth rate per year is 4%.

Alekssandra [29.7K]

Answer:

80,000 + 1.04 to the forth power

Step-by-step explanation:

First term is initial number

Second term is one plus the percent as a decimal (if it’s an increase)

Then to the power of 4 assuming that there are 4 year in between 2016 and this year, 2020

8 0

3 years ago

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0

3 years ago