<img src="https://tex.z-dn.net/?f=solve%20%5C%3A%20%20%5C%5C%20%20%5C%5C%20find%20%5C%3A%20the%20%5C%3A%20area%20%5C%3A%20of%20%

All categories

2 years ago

5C%3A%20rectangle%20%5C%3A%20%20%5C%5C%20%20%5C%5C%20length%20%3D%2011cm%20%5C%5C%20%20%5C%5C%20width%20%3D%209cm" id="TexFormula1" title="solve \: \\ \\ find \: the \: area \: of \: rectangle \: \\ \\ length = 11cm \\ \\ width = 9cm" alt="solve \: \\ \\ find \: the \: area \: of \: rectangle \: \\ \\ length = 11cm \\ \\ width = 9cm" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

N76 [4]2 years ago

5 0

Area = l ×b

$a = l \times b \\ a = 11 \times 9 \\ a = 99$

You might be interested in

The table below describes the smoking habits of a group of asthma sufferers. If one of the 1156 people is randomly selected, fin

Rashid [163]

Answer:

0.554

Step-by-step explanation:

In the figure attached, the table is shown

Total people: 1156

Nonsmoker men + occasional smoker men + regular smoker men + heavy smoker men + heavy smoker women = men + heavy smoker women = 601 + 39 = 640

Probability that the person is a man or a heavy smoker = 640/1156 = 0.554

(Notice that if you directly add heavy smoker and total men you will count twice heavy smoker men)

8 0

3 years ago

I don’t understand these

BaLLatris [955]

So these are basically isolating the variables.
The first equation is 3g + 5 =17.
In order to isolate the variable, we would have to get g by itself, that means 5 would have to go. In order to do this, we would do the opposite. Since it is positive 5 we would add negative 5, in order for it to disappear. This works because a positive 5 and negative 5 cancel each other out. Whatever you do to one side of the equation you have to do to the other, since we subtract 5 on one side we have to subtract 5 on the other. Therefore we would do 17-5.
Now we have 3g=12
We know that 3g is basically 3 multiplied by g. The opposite of multiplication is division.Therefore we would divide by 3 on both sides.
The answer to the first question would be g= 4.
And if you want to check if your answer is correct you plug the value in.
So
3(4) + 5 =17

5 0

2 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

2 years ago

Simplify and write answer without parentheses

Elenna [48]

Answer:

Step-by-step explanation:

Apply the power 2 to the numerator and denominator, separately:

x^2

------------

4y^6

8 0

2 years ago

Louie made 8.1 liters of fruit punch using only grape juice and carbonated water. He used 4.2 liters of grape juice. The equatio

seropon [69]

4.2 +c = 8.1
c = 8.1 -4.2 = 3.9 . . . . subtract 4.2 from both sides

a.) 3.9 liters . . . . . is the appropriate choice

5 0

3 years ago