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KonstantinChe [14]
3 years ago
13

Equation of a line with slope 1/5 through the point (-5, -4)

Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

9514 1404 393

Answer:

  y +4 = (1/5)(x +5)

Step-by-step explanation:

The point-slope form of the equation of a line is useful when you have a given point and slope.

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

Filling in the given values, this is ...

  y +4 = 1/5(x +5)

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Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
A rectangular prism is shown below. What is the surface area, in square centimeters?
Orlov [11]

Answer:

174 square centimetres

Step-by-step explanation:

The formula for finding the surface area of a rectangular prism is

SA = 2LW + 2LH + 2HW

Therefore surface area will be

= 2(11*5) + 2(11*2) +2(2*5)

= 2 * 55 + 2 * 22 + 2 * 10

= (110 + 44 + 20) square cm

Which gives you 174 square centimetres.

3 0
3 years ago
If p(x) = 6x³ + 5x² + 7x - 5, find the coefficient of x³​
denpristay [2]

Answer:

6x

Step-by-step explanation:

because in front of x^3 there is 6x and also the qn has asked to find the coefficient of x^3

7 0
3 years ago
Read 2 more answers
Simplify 4^3 divided by 2 - 3.6 (14.1 - 8.7)
Evgen [1.6K]

Answer:

Step-by-step explanation:

Your answer is 5.4. :)

4 0
3 years ago
Read 2 more answers
A rock dropped on the moon will increase its speed from 0 m/s (its starting
belka [17]
<h2>Hello!</h2>

The answer is:

The correct option is the option D

g=1.63\frac{m}{s^{2}}

<h2>Why?</h2>

To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).

We need to use the following free fall equation:

V_{f}=V_{o}-g*t

Where:

V_{f} is the final speed.

V_{o} is the initial speed.

g is the acceleration due to gravity.

t is the time.

We are given the following information:

V_{f}=8.15\frac{m}{s}

V_{o}=0\frac{m}{s}

t=5seconds

Then, using the formula to isolate the acceleration, we have:

V_{f}=V_{o}-g*t

V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}

Now, substituting we have:

g=\frac{V_{o}-V_{f}}{t}

g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}

Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:

g=1.63\frac{m}{s^{2}}

Hence, the correct option is the option D

g=1.63\frac{m}{s^{2}}

Have a nice day!

7 0
3 years ago
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