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Gnoma [55]
3 years ago
5

NO LINKS I WILL REPORT!!! But help plssss quick plssss Which of these triangles are definitely not congruent to any of the other

s?
Check all that apply.

Mathematics
1 answer:
Vikentia [17]3 years ago
7 0

Answer:

C F D

Step-by-step explanation:

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Using the quadratic formula to solve 7x2 -x = 7, what are the values of x?
Sunny_sXe [5.5K]

Answer:

x=-7

Step-by-step explanation:

7x2-x=7

7x2=14.

14-x=7

When you finished the last step, you will subtract 14 to both sides.

14-x=7

14-14-x=7-14

this will cancel out the 14 on the left.

And will leave you with:

-x=7-14

7-14 is -7.

and this will get you to

-x=-7

To finish this off, you have to turn the negative x/variable, into a positive x/variable.

So, you will divide both sides of the equation by the same term.

-x = -7

into

\frac{-x}{1} =\frac{-7}{1}

and it will be -7.

I hope this helps      :)

8 0
3 years ago
A classroom board is 36 inches wide and 24 inches tall. Cheryl
Gennadij [26K]

Answer:

option B

Step-by-step explanation:

7 0
2 years ago
Find the value of x.
coldgirl [10]

Answer

I guess it my be 8. can you try it ?

Step-by-step explanation:

8 0
3 years ago
I'm very confused on how to solve this problem, can anyone please help? Thanks!
Pepsi [2]

Answer:

.

Step-by-step explanation:

DC = 16 and

DB = 30 so

CB = 14

DB = 30 and

EB = 49 so

EB = 19

5 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 16 + 2x − x^2, [0, 5]
RSB [31]

Answer:

<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>

Step-by-step explanation:

To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.

at x = 0;

f(0) =  16 + 2(0) − 0²

f(0) = 16

at the other end point i.e at x = 5;

f(5) =  16 + 2(5) − 5²

f(5) = 16 + 10-25

f(5)= 26-25

f(5) = 1

The absolute minimum value is 1  and  occurs at x  = 5

The absolute maximum value is 16 and  occurs at x  = 0

5 0
3 years ago
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