All categories

3 years ago

2) Solve for x in the following equation: 9x + 17 - 2x -2 = 50 * Your answer

Mathematics

2 answers:

NARA [144]3 years ago

7 0

Answer:

Step-by-step explanation:

7x plus 15 is 50

7x=35

can i pls have brainliest

ehidna [41]3 years ago

3 0

Answer:

x = 5

Step-by-step explanation:

9x + 17 - 2x - 2 = 50

9x - 2x - 2 = 33

9x - 2x = 35

7x = 35

x = 5

You might be interested in

12 out of every 15

astraxan [27]

Answer: 348 students do not own a cell phone.

Step-by-step explanation:

12 out of 15 = 80%

80% of 435 = 348

4 0

3 years ago

In a class of 35 students, 14 are male. what percent of the class is male?

mars1129 [50]

Total number of students = 35

Number of male students = 14

% of students that are male = $\frac{14}{35} * 100 = \frac{14}{7} * 20 = 2 * 20$ = 40 %

8 0

4 years ago

Plz help me, I have others I need help with

lisov135 [29]

Step-by-step explanation:

That function is a line that goes through the origin (0,0).

You only need one more point to be able to draw it.

Take x=4,5 the corresponding value of y is exactly what you want to know, the number of miles the lava moved after 4,5 hours.

So y = 6 * 4,5 = 27

Your second point is (4,5 , 27).

Now you can draw your line.

6 0

3 years ago

Help me!! I’m very bad at rounding numbers!! What’s 366 rounded to the hundreds place?? help ASAP!

SOVA2 [1]

Answer:

400

Step-by-step explanation:

Tge 6 in the tens place is greater than 5, so you round the 3 up to 4.

3 0

3 years ago

Read 2 more answers

A sample of a radioactive substance decayed to 97% of its original amount after a year. (Round your answers to two decimal place

Andrej [43]

Answer:

a) The half life of the substance is 22.76 years.

b) 5.34 years for the sample to decay to 85% of its original amount

Step-by-step explanation:

The amount of the radioactive substance after t years is modeled by the following equation:

$P(t) = P(0)(1-r)^{t}$

In which P(0) is the initial amount and r is the decay rate.

A sample of a radioactive substance decayed to 97% of its original amount after a year.

This means that:

$P(1) = 0.97P(0)$

Then

$P(t) = P(0)(1-r)^{t}$

$0.97P(0) = P(0)(1-r)^{0}$

$1 - r = 0.97$

$P(t) = P(0)(0.97t)^{t}$

(a) What is the half-life of the substance?

This is t for which P(t) = 0.5P(0). So

$P(t) = P(0)(0.97t)^{t}$

$0.5P(0) = P(0)(0.97t)^{t}$

$(0.97)^{t} = 0.5$

$\log{(0.97)^{t}} = \log{0.5}$

$t\log{0.97} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.97}}$

$t = 22.76$

The half life of the substance is 22.76 years.

(b) How long would it take the sample to decay to 85% of its original amount?

This is t for which P(t) = 0.85P(0). So

$P(t) = P(0)(0.97t)^{t}$

$0.85P(0) = P(0)(0.97t)^{t}$

$(0.97)^{t} = 0.85$

$\log{(0.97)^{t}} = \log{0.85}$

$t\log{0.97} = \log{0.85}$

$t = \frac{\log{0.85}}{\log{0.97}}$

$t = 5.34$

5.34 years for the sample to decay to 85% of its original amount

8 0

4 years ago