<h2>Answer :-</h2>
As we know that,
Pythagoras triplet
1) a² + b² = c²
Let
<h3>Hence, A can't be Pythagoras triplet</h3>
2) a² + b² = c²
<h3>Therefore, B can be Pythagoras triplet</h3>
3)a² + b² = c²
<h3>Hence, C can't be Pythagoras triplet</h3>
4) a² + b² = c²
<h3>Hence, D can't be Pythagoras triplet</h3>
<h2 /><h2>Therefore :-</h2>
Only B can be Pythagoras triplet.
Answer:
A fair die has 6 sides.
There are 3 odd numbers on a fair die so the probability would be 3/6
There are 4 numbers greater than 2 on a fair die o the probability of that would be 4/6
There is only one number that will make it square and that is 4. So the probability would be 1/6
Answer:
119,340
Step-by-step explanation:
So, using the information you have given me, I know,
1/4 = male,
and 1/3 = female
With the same denominator,
3/12 = male,
and 4/12 = female
so, 7/12 = male and female, which means, considering the rest is children,
5/12 = children.
5/12 of 663,432 is,
119340 = children
Hope this helps!!
Let me know if I'm wrong or you need help on a different problem!!
Greater then 187 = 239, 647, 533, 434
Answer:
what is the ?
Step-by-step explanation: