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maw [93]
3 years ago
15

Answer my math question I asked so many times I lost most of points help by

Mathematics
1 answer:
lesantik [10]3 years ago
7 0
Uhh I’m too dumb for that have a great day
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The initial temperature of a cup of tea is 200ºF. The surrounding temperature is 70ºF, and the value of the constant k is 0.6. A
Mazyrski [523]
Newton's cooling model is ΔT = ΔTo * e ^ (-k t)

ΔTo = 200°F - 70°F = 130°F

k = 0.6

t = 2 hours

=> ΔT = 130 * e ^ (-0.6 t) = 130 * e^ (-0.6 * 2) = 130 * e ^ (-1.2)

ΔT = 39.15°F

ΔT = T - Tenvironment => T = ΔT + Tenvironment = 39.15°F + 70°F = 109.15°F ≈ 109 °F.

Answer: T = 109 °F


8 0
4 years ago
Arelli uses 8.4 pints of blue paint and white paint to paint her bedroom walls. 3 4 of this amount is blue paint, and the rest i
Rina8888 [55]

Answer: 2.1 Pints

Step-by-step explanation:

Given

Areli uses 8.4 Pints of blue and White Paint

If the three-fourth is blue paint i.e.

\Rightarrow 8.4\times \dfrac{3}{4}=6.3\ \text{Pints}

The remaining one-fourth is White Paint i.e.

\Rightarrow 8.4\times \dfrac{1}{4}=2.1\ \text{Pints}

5 0
3 years ago
Plz help been stuck on this for awhile
Kazeer [188]

Answer:

<em>d</em> = \sqrt{74}  or 8.60

Step-by-step explanation:

(5, 8) (-2, 3)

Let 5 = x_{1}

     8 = y_{1}

     -2 = x_{2}

     3 = y_{2}

Plug in the values into the equation to get the distance:

<em>d = </em>\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}    }<em />

<em>d </em>= \sqrt{(-2-5)^{2} + (3-8)^{2} }

<em>d = </em>\sqrt{(-7)^{2} + (5)^{2}  }

<em>d</em> =  \sqrt{49 + 25}

<em>d = </em>\sqrt{74} or 8.60

7 0
3 years ago
Q<br> (x + 40)<br> (3x – 20)<br> R<br> S<br> Find m
xz_007 [3.2K]

Answer:

30

Step-by-step explanation:

1. x + 40 = 3x - 20

2. 40 = 2x - 20

3. 60 = 2x

4. 30 = x

5 0
3 years ago
Small point give away! Hope you guys enjoy!
Lostsunrise [7]

Answer:

Wow everyone is being so noice today is today some kind of special occassion?

8 0
3 years ago
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