We have that
f(x) = –4x²<span> + 24x + 13
</span>
we know that
The vertex form for a parabola that opens up or down is:
f(x) = a(x - h)^2 + k
in the given equation, <span>a=-4</span><span>, therefore we add zero to the original equation in the form of </span><span>4h</span>²<span>−4h</span>²
f(x) = –4x² + 24x + 4h²−4h² +13
<span>Factor 4 out of the first 3 terms and group them
</span>f(x) = –4*(x² -6x +h²) +4h² +13
<span>We can find the value of h by setting the middle term equal to -2hx
</span>−2hx=−6x
<span>h=3</span><span> and </span><span>4h</span>²<span>=<span>36
</span></span>f(x) = –4*(x² -6x +9) +36 +13
we know that the term (x² -6x +9) is equals to------> (x-3)²
so
f(x) = –4*(x-3)² +49
the answer isf(x) = –4*(x-3)² +49
Answer:
315 sq. in
Step-by-step explanation:
15 * 21 = 315
Answer:
31.5 (multiplied it after)
Step-by-step explanation:
I love algebra anyways
The ans is in the picture with the steps how i got it
(hope this helps can i plz have brainlist :D hehe)
Answer:
man you got this
Step-by-step explanation:
If f(x) = x + 9 and g(x) = 9x – 4, - 22024651. ... Click on the correct answer. 3 is not in the domain of fºg. 3 is in the domain of fºg. 1. See answer. Add answer+5 pts ... Answer: 3 is in the domain of f(g(x)). Step-by-step explanation: ... What is the domain of the given function? a) {x | x = –6, –1, 0, 3}; {y | y = –7, –2, ...
The domain is all real numbers except 9 (positive)
This is because we can't have 0 in the denominator, and when x equals 9, then the denominator is 0. Anything divided by 0 is undefined, which is why 9 (in this equation) is not included.
